我正在处理两个 pandas 数据帧，并希望匹配来自 df1 的字符串(字符串是通过连接三列派生的)。如何将生成的字符串与 df2 中的列相匹配，如果存在，那么我想提取匹配单元格中的剩余字符串。
df1
id c_id code1 code2 status
1 9 ceo ceo ?
2 9 ned ned
3 9 ned chair
4 2 ed ned
5 2 ned ed
6 9 chair ceo
7 2 chair chair
df2
c_id gender role ex code
2 male chair ,ceo,ned, 2.male.chair.,ceo,ned,
2 male cahir ,chair,ned, 2.male.ned.,chair,ned,
2 female ed ,ned, 2.female.ed.,ned,
6 female ed ,ceo,chair, 6.female.ed.,ceo,chair,
6 male chair ,ed,ceo, 6.male.chair.,ed,ceo,
9 female ed ,ceo,chair, 9.female.ed.,ceo,chair,
9 female chair ,ceo,ned, 9.female.chair.,ceo,ned,
9 male ceo ,chair,(in ft10), 9.male.ceo.,chair,(in ft10),
目标是通过连接 ['c_id', 'code1', 'code2'] 与 df2 匹配来填充列 df1['status'] ['代码']
连接:df1['string'] = df1.apply(lambda x: f'{v["c_id"]}.female.{v["code1"]}.,{v["code2""]},', axis=1)
打印 df1['字符串']
0 9.female.ceo.,ceo,
1 9.female.ned.,ned,
2 9.female.ned.,chair,
3 2.female.ed.,ned,
4 2.female.ned.,ed,
5 9.female.chair.,ceo,
6 2.female.chair.,chair,
当前解决方案:df1['c_id'].map(df2[df2['gender'].str.contains('female')]['ex'])
如果 df['code'] 上有匹配项，df2['ex'] 值基本上就是我需要的值
预期结果: df1
id c_id code1 code2 status
1 9 ceo ceo
2 9 ned ned
3 9 ned chair
4 2 ed ned ,ned,
5 2 ned ed
6 9 chair ceo ,ceo,ned,
7 2 chair chair
我在这方面遇到了严重的障碍，因此非常感谢任何建议或帮助。
最佳答案
您可以根据您的情况使用所需的列进行合并
df1.merge(df2[['c_id','role', 'ex']], left_on = ['c_id', 'code1'], right_on = ['c_id','role'], how = 'left').fillna('')
id c_id code1 code2 role ex
0 1 9 ceo ceo ceo ,chair,(in ft10),
1 2 9 ned ned
2 3 9 ned chair
3 4 2 ed ned ed ,ned,
4 5 2 ned ed
5 6 9 chair ceo chair ,ceo,ned,
6 7 2 chair chair chair ,ceo,ned,
关于python - 如何将一个 pandas 数据帧列中的字符串连接和匹配到另一个数据帧，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54657536/