我想检查输入是否是数字,如果是,则将数字与另一个数字进行比较。
我尝试通过删除 int() 转换来解决一个问题。但这会使 x > 0 无用。
尝试在网上搜索,但没有简单的解决方案。
print("This program prints the sum of a range of numbers from x to y")
print("For example, if x is 10 and y is 50, the program will print the sum of numbers")
print("from 10 to 50")
x = int(input("Please enter the value of x: "))
y = int(input("Please enter the value of y: "))
if x.isnumeric() and y.isnumeric():
if x > 0 and y > 0:
print("Passed")
else:
print("failed")
else:
print("One or more of your inputs are not numeric!")
“int”对象没有“isnumeric”属性作为错误 或者 'str' 和 'int' 实例之间不支持 '>'
最佳答案
您的代码有一些问题。
str.isnumeric适用于字符串,但您尝试在整数上调用它,因此您会收到错误
'int' object has no attribute 'isnumeric'
作为错误如果您不将 x 转换为
int
,并将其保留为str
并尝试做x > 0 and y > 0
,您正在比较字符串和整数,这也是不可能的,因此错误'>' not supported between instances of 'str' and 'int'
要解决此问题,您可以阅读 x
和y
作为字符串,然后在与 0 比较时将其转换为 int,如下所示。
print("This program prints the sum of a range of numbers from x to y")
print("For example, if x is 10 and y is 50, the program will print the sum of numbers")
print("from 10 to 50")
#Read x and y as strings
x = input("Please enter the value of x: ")
y = input("Please enter the value of y: ")
#Check if they are numeric
if x.isnumeric() and y.isnumeric():
#Convert them to int to compare them with 0
if int(x) > 0 and int(y) > 0:
print("Passed")
else:
print("failed")
else:
print("One or more of your inputs are not numeric!")
然后你的输出将如下所示
This program prints the sum of a range of numbers from x to y
For example, if x is 10 and y is 50, the program will print the sum of numbers
from 10 to 50
Please enter the value of x: 20
Please enter the value of y: 40
Passed
This program prints the sum of a range of numbers from x to y
For example, if x is 10 and y is 50, the program will print the sum of numbers
from 10 to 50
Please enter the value of x: 10
Please enter the value of y: 60
Passed
但是等等,这里发生了什么
This program prints the sum of a range of numbers from x to y
For example, if x is 10 and y is 50, the program will print the sum of numbers
from 10 to 50
Please enter the value of x: -20
Please enter the value of y: -40
One or more of your inputs are not numeric!
这里我要注意的是,这个逻辑不适用于负整数
如下所示,isnumeric
对于负整数返回 False
In [1]: '-20'.isnumeric()
Out[1]: False
因此,更好的方法可能是尝试将字符串转换为 int,并在此基础上检查 x 是否为数字
print("This program prints the sum of a range of numbers from x to y")
print("For example, if x is 10 and y is 50, the program will print the sum of numbers")
print("from 10 to 50")
#Read x and y as strings
x = input("Please enter the value of x: ")
y = input("Please enter the value of y: ")
def is_number(s):
#If we can cast string to int, it is an int, else it is not
is_number = False
try:
int(s)
is_number = True
except ValueError:
pass
return is_number
#Check if they are numeric
if is_number(x) and is_number(y):
#Convert them to int to compare them with 0
if int(x) > 0 and int(y) > 0:
print("Passed")
else:
print("failed")
else:
print("One or more of your inputs are not numeric!")
现在代码也适用于负整数
This program prints the sum of a range of numbers from x to y
For example, if x is 10 and y is 50, the program will print the sum of numbers
from 10 to 50
Please enter the value of x: -20
Please enter the value of y: -40
failed
This program prints the sum of a range of numbers from x to y
For example, if x is 10 and y is 50, the program will print the sum of numbers
from 10 to 50
Please enter the value of x: hey
Please enter the value of y: hi
One or more of your inputs are not numeric!
关于python - 比较运算符与 isnumeric() 不兼容?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55979735/