由于 SAT 求解器,我有一个逻辑公式模型的大嵌套 int 列表。 该列表有 100 万个子列表,长度约为 30。
示例数据:
[[-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, -34, 35, 36, -37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, -34, 35, 36, 37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, 34, 35, 36, -37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, 34, 35, 36, 37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, 34, -35, 36, -37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, -31, 32, 33, 34, -35, 36, 37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, 31, 32, 33, 34, -35, 36, -37], [-1, -2, 3, -4, -5, 6, 7, -8, -9, -10, -11, -12, 13, 14, 15, -16, 17, -18, -19, -20, 21, 22, 23, 24, 25, -26, -27, 28, 29, 30, 31, 32, 33, 34, -35, 36, 37]]
我需要检查一个列表(例如 [4,5,6])是否包含属于嵌套列表之一的元素。
假设我的 list 是:
[ [5,12,46,4,99,6],[23,66,99,32,77] ]
如果我用
运行我的程序[4,5,6]
它应该返回true
由于我需要使用不同的列表执行 500 次测试,我猜问题是性能关键。
这是我的计划:
- 对列表进行排序以检查
- 对大嵌套列表进行排序
- 始终首先比较两个最小的数字(假设我搜索 2 并且子列表以 3 开头,我可以继续到下一个子列表)
或者是否有更好的方法,例如使用字典?
(PS:由于我只寻找正数,因此我之前询问了 this question 以消除所有负数。)
最佳答案
使用集:
>>> data = [ [5,12,46,4,99,6],[23,66,99,32,77] ]
>>> set_data = [set(s) for s in data]
>>> set_data
[set([99, 4, 5, 6, 12, 46]), set([32, 66, 99, 77, 23])]
>>> myset = set([4,5,6])
>>> [myset.issubset(s) for s in set_data]
[True, False]
关于python - 快速检查列表是否是嵌套列表元素之一的子列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19870030/