C 循环开关？

Question

这是我的代码:

我的问题是我想用 while 循环来循环 switch 语句，具体取决于得到的 char 响应(在底部)。

我尝试将整个 switch 语句放入 do while 循环中(失败了)。

无论如何，我是这门语言的新手，我想尝试制作一个复杂的程序。

#include <stdio.h>
#include <stdlib.h>
#define LINE  "____________________"
#define TITLE "Tempature Converter"
#define NAME  "Jose Meza II"

char scale, response;
float temp, celTemp, farTemp, kelTemp;

int main() {

printf("\n \t %s \n \t %s \n", LINE, TITLE );
printf("\t by %s \n \t %s \n\n", NAME, LINE );

printf("Enter C for Celsius, F for Fahrenheit, or K for Kelvin: ");
scanf("%c", &scale);
printf("Tempature value: ");
scanf("%f", &temp);

switch (scale)
{
    case ('c'): /* convert to Fahrenheit and Kelvin */
    {
        farTemp = (temp * 9 / 5) + 32;
        kelTemp = temp + 273.15;
        printf("Fahrenheit = %.2f\n", farTemp);
        printf("Kelvin = %.2f\n\n", kelTemp);
        break;
    } /* end case 'c' */
    case ('f'): /* convert to Celsius and Kelvin */
    {
        celTemp = (temp - 32) * 5 / 9;
        kelTemp = (temp - 32) * 5 / 9 + 273.15;
        printf ("Celsius = %.2f\n", celTemp);
        printf ("Kelvin = %.2f\n\n", kelTemp);
        break;
    } /* end case 'f' */
    case ('k'): /* convert to Celsius and Fahrenheit */
    {
        celTemp = temp - 273.15;
        farTemp = (temp - 273.15) * 9 /5 + 32;
        printf("Celsius = %.2f\n", celTemp);
        printf("Fahrenheit = %.2f\n\n", farTemp);
        break;
    } /* end case 'k' */
    default: exit(0); /* no valid temperature scale was given, exit program */
} /* end switch */

printf("Enter in C to Continue, or S to stop: ");
scanf(" %c", &response);

return 0;
}

我能做什么？

我已经尝试过:

do
{
    printf("Enter C for Celsius, F for Fahrenheit, or K for Kelvin: ");
    scanf("%c", &scale);
    printf("Tempature value: ");
    scanf("%f", &temp);

    switch (scale)
    {
        case ('c'): /* convert to Fahrenheit and Kelvin */
        {
            farTemp = (temp * 9 / 5) + 32;
            kelTemp = temp + 273.15;
            printf("Fahrenheit = %.2f\n", farTemp);
            printf("Kelvin = %.2f\n\n", kelTemp);
            break;
        } /* end case 'c' */
        case ('f'): /* convert to Celsius and Kelvin */
        {
            celTemp = (temp - 32) * 5 / 9;
            kelTemp = (temp - 32) * 5 / 9 + 273.15;
            printf ("Celsius = %.2f\n", celTemp);
            printf ("Kelvin = %.2f\n\n", kelTemp);
            break;
        } /* end case 'f' */
        case ('k'): /* convert to Celsius and Fahrenheit */
        {
            celTemp = temp - 273.15;
            farTemp = (temp - 273.15) * 9 /5 + 32;
            printf("Celsius = %.2f\n", celTemp);
            printf("Fahrenheit = %.2f\n\n", farTemp);
            break;
        } /* end case 'k' */
        default: exit(0); /* no valid temperature scale was given, exit     program */
    } /* end switch */

    printf("Enter in C to Continue, or S to stop: ");
    scanf(" %c", &response);
}
while(response == 'c');

Answer 1

最常见的方法是使用 do-while 循环。进行以下更改

<删除> 1. 初始化对“C”的“响应”。 2. 将`switch` case 以及接下来的`printf()` 和`scanf()` 放入`do..while()` 循环中。 3. 在 `while ()` 条件中，检查 `while (c == `C`)`。 <小时/>

修改后，问题似乎是

scanf("%c", &scale);

您需要在%c之前有一个空格，例如

scanf(" %c", &scale);

避免最后在C之后出现ENTER [\n]。