我编写了一个程序,它会在 printf
之前执行两次 scanf
操作,并输出两个应该是单个 printf
的内容。该问题似乎从要求用户输入 1 到 4 之间的数字以查看输入天数的平均温度时开始出现。
我不确定是什么导致了这种双重输入和输出以及偶尔的延迟。这是我的代码:
#include <stdio.h>
#include <stdlib.h>
int main (void) {
int i;
int limit;
int day[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int high[10], low[10];
printf("---===IPC Temperature Analyzer V2.0===---\n");
printf("Please enter the number of days between 3 and 10, inclusive: ");
scanf("%d", &limit);
while (limit <= 2 || limit >= 11) {
printf("Invalid entry, please enter a number between 3 and 10, inclusive: ");
scanf("%d", &limit);
}
for (i = 0; i < limit; i++) {
printf("Day %d - High: ", day[i]);
scanf("%d", &high[i]);
printf("Day %d - Low: ", day[i]);
scanf("%d", &low[i]);
}
printf("\nDay Hi Low\n");
for (i = 0; i < limit; i++) {
printf("%d %d %d\n", day[i], high[i], low[i]);
}
int max = 0;
int min = 0;
for (i = 0; i < limit; i++) {
if (high[max] < high[i])
max = i;
if (low[min] > low[i])
min = i;
}
printf("\nHighest temperature was: %d on day %d\n", high[max], day[max]);
printf("Lowest temperature was: %d on day %d\n", low[min], day[min]);
int n;
do {
printf("\nEnter a number between 1 and 4 to see the average temperature "
"for the entered number of days, enter a negative number to exit:");
scanf("%d\n", &n);
while (n > 4) {
printf("Invalid entry, please enter a number between 1 and 4, inclusive: ");
scanf("%d", &n);
}
while (n < 0) {
printf("Goodbye!\n");
exit(0);
}
float avgSum = 0.0;
for (i = 0; i < n; i++) {
float avgOfDay = (high[i] + low[i]) / 2.0;
avgSum += avgOfDay;
}
float overallAvg = avgSum / n;
printf("The average temperature up to day %d is: %.2f\n", day[n - 1], overallAvg);
} while (n > 0 || n < 4);
return 0;
}
示例输出:
Enter a number between 1 and 4 to see the average temperature for the entered number of days, enter a negative number to exit:5
5
Invalid entry, please enter a number between 1 and 4, inclusive: Invalid entry, please enter a number between 1 and 4, inclusive: 3
The average temperature up to day 3 is: 2.50
Enter a number between 1 and 4 to see the average temperature for the entered number of days, enter a negative number to exit: 2
2
The average temperature up to day 2 is: 2.75
Enter a number between 1 and 4 to see the average temperature for the entered number of days, enter a negative number to exit: -1
The average temperature up to day 2 is: 2.75
Enter a number between 1 and 4 to see the average temperature for the entered number of days, enter a negative number to exit: -1
Goodbye!
最佳答案
您所描述的问题可以追溯到scanf()
do
开头的声明循环:
scanf("%d\n", &n);
格式字符串末尾的换行符是个问题。当scanf()
在格式字符串中遇到空白字符,它会匹配输入流中的空白字符,直到遇到非空白字符。问题是,当您按 Enter 键输入您的号码时,这只是另一个空白字符,因此 scanf()
贪婪地继续等待更多输入,直到出现非空白字符或 EOF
遇到。当用户此时输入非空白字符时,scanf()
空格匹配失败,输入的字符保留在输入流中,scanf()
最后返回到调用函数,最后是下一个scanf()
拿起刚刚被拒绝的角色。这就是您观察到的零星响应的原因。
解决这个问题很简单。只需删除 \n
从格式字符串的末尾开始。通常情况下,格式字符串末尾的空白字符是错误的做法。
代码中还存在其他问题。测试结束do
循环应该是:
while (n > 0 && n < 4);
退出值的测试会更好,如 if
语句而不是 while
循环,测试应该是 n < 1
而不是n < 0
避免被零除错误:
if (n < 1) {
printf("Goodbye!\n");
exit(0);
}
看来你应该将输入提示改为:
printf("\nEnter a number between 1 and 3 to see the average temperature for the entered number of days, enter a negative number to exit:");
如果用户选择4
这里,但只输入了3天的数据,计算将访问high[]
中未初始化的值。和low[]
数组。您还需要将此输入循环更改为:
while (n > 3) {
printf("Invalid entry, please enter a number between 1 and 3, inclusive: ");
scanf("%d", &n);
}
可能还有其他问题,但这应该能让事情正常运行。
关于c - 循环重复 scanf 和 printf,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42287516/