我已经为非正则化逻辑回归成本函数和查找梯度编写了一些代码，但无论我尝试什么，我的代码都会返回相同的 TypeError。
我已经尝试过代码的矢量化和 for 循环实现，但没有任何效果。我还想指出，评分者总是给我的成本函数打满分，但不给求偏导数的代码评分。我的结果始终与预期成本相符，但渐变部分没有返回任何内容。
它说这是成本: J(𝜃)=1𝑚Σ𝑖=1𝑚[−𝑦(𝑖)log(ℎ𝜃(𝑥(𝑖)))−(1−𝑦(𝑖))log(1−ℎ𝜃(𝑥(𝑖)))]
这是偏导数: ∂𝐽(𝜃)∂𝜃𝑗=1𝑚Σ𝑖=1𝑚(ℎ𝜃(𝑥(𝑖))−𝑦(𝑖))𝑥(𝑖)𝑗
(通过类(class)，我可以验证这是正确的)
def costFunction(theta, X, y):
# Initialize some useful values
m = y.size # number of training examples
# You need to return the following variables correctly
J = 0
grad = np.zeros(theta.shape)
# ====================== YOUR CODE HERE ============
for i in range(m):
hypothesis = sigmoid(np.dot(theta.T, X[i, :]))
J += y[i] * math.log(hypothesis) + (1 - y[i]) * math.log(1 - hypothesis)
for j in range(n):
grad = (hypothesis - y[i]) * X[i, j]
J = (-1 / m) * J
grad = (1 / m) * grad
# =============================================================
return J, grad
# Initialize fitting parameters
initial_theta = np.zeros(n+1)
cost, grad = costFunction(initial_theta, X, y)
print('Cost at initial theta (zeros): {:.3f}'.format(cost))
print('Expected cost (approx): 0.693\n')
print('Gradient at initial theta (zeros):')
#print('\t[{:.4f}, {:.4f}, {:.4f}]'.format(*grad))
print('Expected gradients (approx):\n\t[-0.1000, -12.0092, -11.2628]\n')
# Compute and display cost and gradient with non-zero theta
test_theta = np.array([-24, 0.2, 0.2])
cost, grad = costFunction(test_theta, X, y)
print('Cost at test theta: {:.3f}'.format(*cost))
print('Expected cost (approx): 0.218\n')
print('Gradient at test theta:')
print('\t[{:.3f}, {:.3f}, {:.3f}]'.format(*grad))
print('Expected gradients (approx):\n\t[0.043, 2.566, 2.647]')
我希望输出是:
Cost at initial theta (zeros): 0.693
Expected cost (approx): 0.693
Gradient at initial theta (zeros):
[-0.1000, -12.0092, -11.2628]
Expected gradients (approx):
[-0.1000, -12.0092, -11.2628]
但我得到以下信息:
Cost at initial theta (zeros): 0.693
Expected cost (approx): 0.693
Gradient at initial theta (zeros):
Expected gradients (approx):
[-0.1000, -12.0092, -11.2628]
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-35-ab2a7b541269> in <module>()
15 cost, grad = costFunction(test_theta, X, y)
16
---> 17 print('Cost at test theta: {:.3f}'.format(*cost))
18 print('Expected cost (approx): 0.218\n')
19
TypeError: format() argument after * must be an iterable, not numpy.float64
最佳答案
查看函数 costFunction() 时，返回值 J(您分配给 cost)是一个标量。因此，不能用星号*解包，应该直接传递给字符串格式化方法:
print('Cost at test theta: {:.3f}'.format(cost)) # passing 'cost' without the star
关于python - 我的 Andrew Ng 类(class)的逻辑回归梯度 Python 代码不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/58793912/