我有两个节点。我想单击一个节点,将光标拖动到另一个节点,并在释放光标后用一条线连接这两个节点。
我已经设置了所有事件处理程序 - 拖放线可以工作,但它不会绑定(bind)到第二个节点。
public class LinkHandler {
static Node hoverNode;
}
该类用于查找光标悬停在哪个节点上。
private void setLinkHandlers(Node node) {
Line line = new Line();
this.getChildren().add(line);
// On mouse hover, set LinkHandler.hoverNode
node.setOnMouseDragEntered( (MouseEvent mouseEvent) -> {
LinkHandler.setHoverNode(node);
System.out.println(node);
});
// On mouse exit, remove LinkHandler.hoverNode
node.setOnMouseDragExited( (MouseEvent mouseEvent) -> {
// PLEASE NOTE: I have tried commenting and uncommenting the line below. Neither works.
// LinkHandler.setHoverNode(null);
});
// On mouse press, set Line startpoint
node.setOnMousePressed( (MouseEvent mouseEvent) -> {
// Stop BorderPane from being dragged
LinkHandler.isConnecting = true;
// Bind startpoint to node position
line.startXProperty().bind(node.layoutXProperty());
line.startYProperty().bind(node.layoutYProperty());
});
// On mouse released, either bind Line to LinkHandler.hoverNode, or remove if hoverNode = null
node.setOnMouseReleased( (MouseEvent mouseEvent) -> {
// Allow BorderPane to be dragged again
LinkHandler.isConnecting = false;
// If there is a node to connect to...
if(LinkHandler.getHoverNode() != null) {
// Bind end position to the node's position
line.endXProperty().bind(LinkHandler.getHoverNode().layoutXProperty());
line.endYProperty().bind(LinkHandler.getHoverNode().layoutYProperty());
} else {
// Otherwise print error
System.out.println("Not hovering over a node. Cannot create connection.");
}
});
// Temporarily bind Line endpoint to mouse position.
node.setOnMouseDragged( (MouseEvent mouseEvent) -> {
line.setEndX(mouseEvent.getX());
line.setEndY(mouseEvent.getY());
});
}
这是很多代码,所以我会尝试总结一下:
- 当dragEntered时,将LinkHandler.hoverNode设置为该节点
- 拖拽退出时,将LinkHandler.hoverNode设置为null
- 当鼠标按下时,将Line起始位置绑定(bind)到该节点位置
- 当mouseDragged时,临时设置Line end位置为mousePosition
- 当mouseReleased时,将Line结束位置绑定(bind)到LinkerHandler.hoverNode位置,或者当hoverNode为null时移除Line。
我相信问题出在这个片段中:
// On mouse hover, set LinkHandler.hoverNode
node.setOnMouseDragEntered( (MouseEvent mouseEvent) -> {
LinkHandler.setHoverNode(node);
System.out.println(node);
});
// On mouse exit, remove LinkHandler.hoverNode
node.setOnMouseDragExited( (MouseEvent mouseEvent) -> {
// LinkHandler.setHoverNode(null);
});
我认为这没有被正确调用。此代码适用的节点是 BorderPane 的子节点,它具有自己的 onMouseDrag 功能 << 这也可能会导致问题。
提前致谢,如果这个问题有点含糊,抱歉。我试图具体一点。
最佳答案
请注意,您永远不会初始化完整的拖动,因此事件永远不会传递到拖动的起始节点以外的节点。要更改此设置,请为起始节点调用 startFullDrag()
。
以下示例演示了如何将线条捕捉到圆
的中心:
public static Circle createCircle(double x, double y) {
return new Circle(x, y, 20, Color.BLACK.deriveColor(0, 1, 1, 0.5));
}
@Override
public void start(Stage primaryStage) {
Node[] circles = new Node[]{
createCircle(40, 40),
createCircle(240, 40),
createCircle(40, 240),
createCircle(240, 240)
};
Pane root = new Pane(circles);
class DragStartHandler implements EventHandler<MouseEvent> {
public Line line;
@Override
public void handle(MouseEvent event) {
if (line == null) {
Node sourceNode = (Node) event.getSource();
line = new Line();
Bounds bounds = sourceNode.getBoundsInParent();
// start line at center of node
line.setStartX((bounds.getMinX() + bounds.getMaxX()) / 2);
line.setStartY((bounds.getMinY() + bounds.getMaxY()) / 2);
line.setEndX(line.getStartX());
line.setEndY(line.getStartY());
sourceNode.startFullDrag();
root.getChildren().add(0, line);
}
}
}
DragStartHandler startHandler = new DragStartHandler();
EventHandler<MouseDragEvent> dragReleaseHandler = evt -> {
if (evt.getGestureSource() == evt.getSource()) {
// remove line, if it starts and ends in the same node
root.getChildren().remove(startHandler.line);
}
evt.consume();
startHandler.line = null;
};
EventHandler<MouseEvent> dragEnteredHandler = evt -> {
if (startHandler.line != null) {
// snap line end to node center
Node node = (Node) evt.getSource();
Bounds bounds = node.getBoundsInParent();
startHandler.line.setEndX((bounds.getMinX() + bounds.getMaxX()) / 2);
startHandler.line.setEndY((bounds.getMinY() + bounds.getMaxY()) / 2);
}
};
for (Node n : circles) {
// register handlers
n.setOnDragDetected(startHandler);
n.setOnMouseDragReleased(dragReleaseHandler);
n.setOnMouseDragEntered(dragEnteredHandler);
// add info allowing to identify this node as drag source/target
n.setUserData(Boolean.TRUE);
}
root.setOnMouseReleased(evt -> {
// mouse released outside of a target -> remove line
root.getChildren().remove(startHandler.line);
startHandler.line = null;
});
root.setOnMouseDragged(evt -> {
if (startHandler.line != null) {
Node pickResult = evt.getPickResult().getIntersectedNode();
if (pickResult == null || pickResult.getUserData() != Boolean.TRUE) {
// mouse outside of target -> set line end to mouse position
startHandler.line.setEndX(evt.getX());
startHandler.line.setEndY(evt.getY());
}
}
});
Scene scene = new Scene(root, 280, 280);
primaryStage.setScene(scene);
primaryStage.show();
}
关于JavaFx通过拖放的方式用一条线连接两个子节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39658505/