我有这个页面,老师可以邀请学生加入该平台。这工作得很好,但现在我想在同一页面上实现多个邀请。简而言之,现在有一种表格可以一次邀请 1 名学生,但我想将其扩展为一次邀请 5 名学生。
这是邀请 1 名学生的页面:
<div class="container">
<div class="wrapper">
<form class="form-activate" th:action="@{/invite}" method="post" th:object="${user}">
<h2 class="form-activate-heading" th:text="#{invite.title}">Nodig een student uit</h2>
<p th:text="#{invite.email}">Vul hier het e-mailadres in van de student die je wil uitnodigen:</p>
<div class="form-group">
<input type="text" name="email" id="email" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<input type="submit" class="btn btn-secondary" value="Invite" th:attr="value=#{invite.enter}"/>
</div>
</div>
</form>
</div>
现在我尝试为 2 个用户修改此页面:
<div class="container">
<div class="wrapper">
<form class="form-activate" th:action="@{/invite}" method="post">
<h2 class="form-activate-heading" th:text="#{invite.title}">Nodig een student uit</h2>
<p th:text="#{invite.email}">Vul hier het e-mailadres in van de student die je wil uitnodigen:</p>
<div class="form-group" th:object="${user}">
<input type="text" name="email" th:field="*{email}" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="form-group" th:object="${user}">
<input type="text" name="email" th:field="*{email}" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<input type="submit" class="btn btn-secondary" value="Invite" th:attr="value=#{invite.enter}"/>
</div>
</div>
</form>
</div>
然后在我的帖子方法中我尝试这样做:
@RequestMapping(value="/invite", method = RequestMethod.POST)
public ModelAndView SendInvite(ModelAndView modelAndView, @ModelAttribute User user1, @ModelAttribute User user2, BindingResult bindingResult, RedirectAttributes redirectAttributes, HttpServletRequest request){
List<User> students = new ArrayList<>();
students.add(user1);
students.add(user2);
for (User user : students) {
但是页面甚至不再加载,这是我的获取方法:
@RequestMapping(value="/invite", method = RequestMethod.GET)
public ModelAndView showInvitePage(ModelAndView modelAndView, @ModelAttribute User user){
return modelAndView;
}
这给了我以下错误:
路径 [] 上下文中 servlet [dispatcherServlet] 的 Servlet.service() 抛出异常 [请求处理失败;嵌套异常是 org.thymeleaf.exceptions.TemplateProcessingException:执行处理器 'org.thymeleaf.spring4.processor.attr.SpringInputGeneralFieldAttrProcessor' (teacher/invite:20)] 时出错,根本原因 java.lang.IllegalStateException:BindingResult 和 bean 名称“user”的普通目标对象都不能作为请求属性 在 org.springframework.web.servlet.support.BindStatus.(BindStatus.java:144)
我想做的事情有可能吗?
编辑:我正在尝试实现 Aleksandrs 给我的解决方案,但 Spring 抛出错误:
@RequestMapping(value="/invite", method = RequestMethod.GET)
public ModelAndView showInvitePage(ModelAndView modelAndView){
List<String> emailList = new ArrayList<>();
modelAndView.addObject(emailList);
return modelAndView;
}
@RequestMapping(value="/invite", method = RequestMethod.POST)
public ModelAndView SendInvite(ModelAndView modelAndView, List<String> emailList){
System.out.println(emailList.get(0));
尽管我已在 Get 方法中实例化了 emailList,但仍收到以下错误:
嵌套异常是org.springframework.beans.BeanInstantiationException:无法实例化[java.util.List]:指定的类是一个接口(interface)],其根本原因 org.springframework.beans.BeanInstantiationException:无法实例化[java.util.List]:指定的类是一个接口(interface)
编辑2:
终于成功了,感谢 Aleksandrs 的帮助!解决方案:
@RequestMapping(value="/teacher/invite", method = RequestMethod.GET)
public ModelAndView showInvitePage(ModelAndView modelAndView){
logger.info("Entered showInvitePage function");
List<String> email = new ArrayList<>();
modelAndView.addObject("email", email);
return modelAndView;
}
@RequestMapping(value="/invite", method = RequestMethod.POST)
public ModelAndView SendInvite(ModelAndView modelAndView, @AuthenticationPrincipal User currentUser, @RequestParam List<String> email){
email.forEach(address -> {
// send the invites
});
邀请页面:
<form class="form-activate" th:action="@{/invite}" method="post" >
<p th:text="#{invite.email}">Vul hier het e-mailadres in van de student die je wil uitnodigen:</p>
</div>
<div class="form-group">
<input type="text" name="email" id="email" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="form-group">
<input type="text" name="email" id="email2" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="form-group">
<input type="text" name="email" id="email3" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<input type="submit" class="btn btn-secondary" value="Invite" th:attr="value=#{invite.enter}"/>
</div>
</div>
</form>
最佳答案
正如 Pandian 所说,“用户”绑定(bind)了两次,但在这种情况下,您可以使用简单的数组将字符串列表传递到 Controller 中。因为实际用户必须具有许多模板中不存在的字段。因此可以在模板中重新评论使用类似的内容:
<form class="form-activate" th:action="@{/invite}" method="post">
<h2 class="form-activate-heading" th:text="#{invite.title}">Nodig een student uit</h2>
<p th:text="#{invite.email}">Vul hier het e-mailadres in van de student die je wil uitnodigen:</p>
<div class="form-group">
<input type="text" name="email[]" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="form-group">
<input type="text" name="email[]" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<input type="submit" class="btn btn-secondary" value="Invite"
th:attr="value=#{invite.enter}"/>
</div>
</div>
</form>
在 Controller 中:
@RequestMapping(value = "/invite", method = RequestMethod.POST)
public ModelAndView SendInvite(List<String> emailAddressList) {
// some stuff here
}
编辑:
所以,我不确定我的 JavaScript 代码是否有效,但在你的情况下 HTML 必须是这样的:
<form class="form-activate" th:action="@{/invite}" method="post" id="myForm">
<h2 class="form-activate-heading" th:text="#{invite.title}">Nodig een student uit</h2>
<p th:text="#{invite.email}">Vul hier het e-mailadres in van de student die je wil uitnodigen:</p>
<div class="form-group">
<input type="text" name="email[]" id="email" class="form-control input-lg" data-validation="email"
placeholder="Email" tabindex="2" th:attr="placeholder=#{general.email}"/>
<span style="cursor: pointer;"
onclick="myForm.innerHTML = myForm.innerHTML + '' + this.parentNode.cloneNode(true);">+</span>
</div>
<div class="row">
<div class="col-xs-6 col-sm-6 col-md-6">
<input type="submit" class="btn btn-secondary" value="Invite"
th:attr="value=#{invite.enter}"/>
</div>
</div>
</form>
在 Controller 中我会尝试这样做:
@RequestMapping(value = "/invite", method = RequestMethod.POST)
public ModelAndView SendInvite(ModelAndView modelAndView, @RequestParam List<String> email) {
email.stream()
.forEach(address -> {
User u = userService.findByEmail(address);
if (u == null) {
// send email here for current user;
}
});
// some other stuff
}
如果你能告诉我一些测试密码,我可以尝试在我的电脑上运行它。
关于java - post方法中相同类型的多个模型属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49647649/