java - 如何在 Spring Security 中创建自定义 UserDetail 对象

Question

我已经为 Spring Security 构建了我的自定义身份验证管理器，它是这样的

   public class AccountAuthenticationProvider implements  AuthenticationProvider{

    @Autowired
    private AuthenticationService authService;

    @Override
    public Authentication authenticate(Authentication authentication) throws AuthenticationException {

        String userName = authentication.getName();
        String password = (String)authentication.getCredentials();

        if(authService.isValid(userName,password)){
            List<GrantedAuthority> grantedAuthorityList = new ArrayList<GrantedAuthority>();
            grantedAuthorityList.add(new SimpleGrantedAuthority("ROLE_USER"));
            SecurityContext securityContext = new SecurityContextImpl();
            return  new UsernamePasswordAuthenticationToken(userName,password);
        }

        return null;
    }


    public void setAuthService(AuthenticationService authService) {
        this.authService = authService;
    }

    @Override
    public boolean supports(Class<?> authentication) {
        return true;
    }

}

但是如何创建自己的自定义 UserDetail 对象？我将用它来存储与帐户相关的值

Answer 1

您需要实现 UserDetailsS​​ervice 并覆盖 loadUserByUsername 方法以返回您自定义的 UserDetails 类。

检查以下链接:

http://www.javaroots.com/2013/03/how-to-use-custom-dao-classe-in-spring.html http://www.javacodegeeks.com/2012/08/spring-security-implementing-custom.html