以下 Actor 没有名字。在 libgdx 中，为每个 Actor 分配名称的最佳方式是什么？
public class JewelsMainActivity implements ApplicationListener, InputProcessor {
private Vector2 point = new Vector2();
public TextureAtlas jewelsAtlas;
public Texture jewels;
private SpriteBatch batch;
public Actor[][] actors = new Actor[10][10];
public Stage stage;
public int gridSize;
@Override
public void create() {
stage = new Stage(800, 600, false);
gridSize = 10;
batch = new SpriteBatch();
jewels = new Texture(Gdx.files.internal("assets/gems1.png"));
jewelsAtlas = new TextureAtlas(Gdx.files.internal("assets/pack"));
for (int z = 0; z < gridSize; z++) {
for (int x = 0; x < gridSize; x++) {
Random r = new Random();
int j = r.nextInt(2)+1;
actors[x][z] = new Image(jewelsAtlas.findRegion(""+j+""));
actors[x][z].x = x*56; //each gem is 56*56 width / height
actors[x][z].y = z*56;
// Actor [x][z].name = " Actor "+x+z; //不能使用上面的这个，因为它不允许......
stage.addActor(actors[x][z]);
}
}
Gdx.input.setInputProcessor(this);
}
@Override
public void render() {
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
batch.begin();
stage.draw();
batch.end();
}
@Override
public boolean touchDown(int x, int y, int pointer, int button) {
stage.toStageCoordinates(Gdx.input.getX(), Gdx.input.getY(), point);
Actor actor = stage.hit(point.x, point.y);
if (actor != null){
Gdx.app.log("name", actor.name);
//actor.name 为空
Gdx.app.log("hashCode", ""+actor.hashCode());
((Image)actor).color.set((float)Math.random(), (float)Math.random(), (float)Math.random(), 0.5f + 0.5f * (float)Math.random());
}
return false;
}
.... .... ....
}
最佳答案
该名称是最终名称，因此必须在构造函数中定义。
你在哪里
actors[x][z] = new Image(jewelsAtlas.findRegion(""+j+""));
使用
actors[x][z] = new Image(jewelsAtlas.findRegion(""+j+""), Scaling.none, Align.CENTER, "myawesomenewname");
关于java - 如何在 libgdx 中命名 Actor？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/10267599/