我有一个用于获取我的推文的 java 程序，下面是代码
public class TwitterTest {
public static void main(String[] args) {
Twitter twitter = new TwitterFactory().getInstance();
// My Applications Consumer and Auth Access Token
//twitter.setOAuthConsumer("67MIcbC1X6mbpaEqxa7YTd1hDPIdLb5bLKf4TxIRLAsX63DgFQ", "7HHjSHJ6Rjxx4ASC2465AlWBG");
twitter.setOAuthAccessToken(new AccessToken("s1y1iAhG5nsXTrE9OVAsqMtqiLIP4QKT8CmTRVgV9LC3O", "110445397-Cf3l9NAK4iD8VAERXp0ZMKnAfWx9KywuJs3OSdkF"));
try {
ResponseList<Status> a = twitter.getUserTimeline(new Paging(1,5));
for(Status b: a) {
System.out.println(b.getText());
}
}catch(Exception e ){
}
}
}
下面是我得到的错误
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TwitterException{exceptionCode=[b64d2231-309f0452], statusCode=403, message=SSL is required, code=92, retryAfter=-1, rateLimitStatus=RateLimitStatusJSONImpl{remaining=178, limit=180, resetTimeInSeconds=1430935706, secondsUntilReset=775}, version=3.0.3}
错误原因是什么？
最佳答案
您需要启用 SSL。查看此主题以获取更多信息:"SSL is required" exception while requesting OAuthRequest Token using Twitter4J library
关于java - 使用 Twitter4j 获取推文，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30084112/