java - JDBC - 如何仅检索没有时间的日期(ORACLE 12c)

Question

我正在尝试构建一个小型控制台应用程序，用于接收公司员工的 ID 并打印他/她的详细信息。一切都很顺利，但是当涉及到员工的任命日期时，它会给出日期和时间。 示例:“2005-03-10 00:00:00.0”

我在这里想做的是，我只想要“2005-03-10”。那怎么办呢？代码如下:

public static void main(String[] args) {

    Scanner read = new Scanner(System.in);
    try
    {
    Class.forName("oracle.jdbc.driver.OracleDriver");
    Connection conn = DriverManager.getConnection("jdbc:oracle:thin:sys/password@//localhost:1521:xe");
    Statement st = conn.createStatement();

    System.out.print("Enter the id of employee: ");
    String id = read.next();

    String sql = "SELECT E.EMP_NAME, D.DEPT_NAME, ES.ROLE, ES.DATE_OF_APPOINTMENT, S.SALARY "
            + "FROM EMPLOYEE E, DEPARTMENT D, DEPARTMENT_ROLE DR, EMPLOYEE_SERVICE ES, SALARY S "
            + "WHERE E.EMP_ID = ES.EMP_ID AND E.EMP_ID=S.EMP_ID AND D.DEPT_ID=DR.DEPT_ID AND DR.ROLE=ES.ROLE "
            + "AND E.EMP_ID='"+id+"'";

    ResultSet rs = st.executeQuery(sql);

    while(rs.next()){
        System.out.println("\n\nEmployee Name\t: "+rs.getString(1)+"\nDepartment\t: "+rs.getString(2)
                +"\nRole\t\t: "+rs.getString(3)+"\nAppointed On\t: "+rs.getString(4)+"\nSalary\t\t: "+rs.getString(5));
    }
    st.close();
    conn.close();
    read.close();
    }
    catch(SQLException e){
        e.printStackTrace();
    }
    catch(Exception se){
        se.printStackTrace();
    }
}

输出如下所示:

输入员工 ID:CCT003

员工姓名:约瑟夫·布朗

部门:人力资源

角色:执行招聘人员

任命时间:2006-02-13 00:00:00.0

薪资:118000

请帮忙。 谢谢。

Answer 1

由于您是以字符串形式检索数据，因此您只需再添加一个步骤并对其进行格式化

String sql = "SELECT E.EMP_NAME, D.DEPT_NAME, ES.ROLE, TO_CHAR(ES.DATE_OF_APPOINTMENT,'YYYY-MM-DD') AS DATE_OF_APPOINTMENT, S.SALARY "
            + "FROM EMPLOYEE E, DEPARTMENT D, DEPARTMENT_ROLE DR, EMPLOYEE_SERVICE ES, SALARY S "
            + "WHERE E.EMP_ID = ES.EMP_ID AND E.EMP_ID=S.EMP_ID AND D.DEPT_ID=DR.DEPT_ID AND DR.ROLE=ES.ROLE "
            + "AND E.EMP_ID='"+id+"'";