我想使用 ResteasyClient 访问 Power Bi 中的组列表,我想使用服务主体(仅应用程序 token )的身份验证形式。
我有应用程序 ID(客户端),应用程序 secret ( key )范围 = Group.Read.All,访问 token URL https://login.microsoftonline.com/common/oauth2/token和授权类型 = 客户端凭据。
public static String getAccessToken(OAuth2Details oauthDetails) {
HttpPost post = new HttpPost(oauthDetails.getAuthenticationServerUrl());
String clientId = oauthDetails.getClientId();
String clientSecret = oauthDetails.getClientSecret();
String scope = oauthDetails.getScope();
List<BasicNameValuePair> parametersBody = new ArrayList<BasicNameValuePair>();
parametersBody.add(new BasicNameValuePair(OAuthConstants.GRANT_TYPE,
oauthDetails.getGrantType()));
parametersBody.add(new BasicNameValuePair(OAuthConstants.CLIENT_ID,
clientId));
parametersBody.add(new BasicNameValuePair(
OAuthConstants.CLIENT_SECRET, clientSecret));
if (isValid(scope)) {
parametersBody.add(new BasicNameValuePair(OAuthConstants.SCOPE,
scope));
}
HttpClient client = new DefaultHttpClient();
HttpResponse response = null;
String accessToken = null;
try {
post.setEntity(new UrlEncodedFormEntity(parametersBody, HTTP.UTF_8));
response = client.execute(post);
int code = response.getStatusLine().getStatusCode();
if (code == OAuthConstants.HTTP_UNAUTHORIZED) {
if (log.isDebugEnabled()) {
log.debug("Authorization server expects Basic authentication");
}
// Add Basic Authorization header
post.addHeader(
OAuthConstants.AUTHORIZATION,
getBasicAuthorizationHeader(oauthDetails.getClientId(),
oauthDetails.getClientSecret()));
if (log.isDebugEnabled()) {
log.debug("Retry with client credentials");
}
post.releaseConnection();
response = client.execute(post);
code = response.getStatusLine().getStatusCode();
if (code == 401 || code == 403) {
if (log.isDebugEnabled()) {
log.debug("Could not authenticate using client credentials.");
}
throw new RuntimeException(
"Could not retrieve access token for client: "
+ oauthDetails.getClientId());
}
}
Map<String, String> map = handleResponse(response);
accessToken = map.get(OAuthConstants.ACCESS_TOKEN);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return accessToken;
}
谢谢你。
我有一个许可证(powerbi,)我应该能够用用户名和密码生成 token ,但它不起作用。我的回复当前状态为 400,但我的网址似乎是正确的。
基本上我有这个
client_id=affxxx
client_secret=cxxx
username=xxx
password=xxx
authentication_server_url=https://login.microsoftonline.com/common/oauth2/token
grant_type=client_credentials
client_credentials=client_credentials
当前响应
HTTP/1.1 400 Bad Request [Cache-Control: no-cache, no-store, Pragma: no-cache, Content-Type: application/json; charset=utf-8, Expires: -1, Strict-Transport-Security: max-age=31536000; includeSubDomains, X-Content-Type-Options: nosniff, x-ms-request-id: 11cd7b41-eaf6-49d4-b6a6-3b19a5569c00, x-ms-ests-server: 2.1.9288.13 - AMS1 ProdSlices, P3P: CP="DSP CUR OTPi IND OTRi ONL FIN", Set-Cookie: fpc=AlrZG0Zj8XhGpMfGBgQKR1Y; expires=Wed, 25-Sep-2019 13:03:32 GMT; path=/; secure; HttpOnly, Set-Cookie: x-ms-gateway-slice=prod; path=/; secure; HttpOnly, Set-Cookie: stsservicecookie=ests; path=/; secure; HttpOnly, Date: Mon, 26 Aug 2019 13:03:32 GMT, Content-Length: 468]
最佳答案
通过 http post 请求进行的身份验证握手中存在错误。
收到的结果总是以相同类型的错误结束:
HTTP/1.1 400 Bad Request
我们需要将标题“ Accept ”明确设置为“ None ”:
post.addHeader("Accept", "None");
关于java - 使用 HttpClient 通过 java 客户端访问 power Bi 组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57609701/