mysql - 真实世界总销售额 SQL 查询

Question

我对 SQL 相当陌生，在解决问题时遇到困难。

“销售人员在销量最高的五种产品中每一种至少销售一种，其所有产品的总销售额是多少？”确保查询按降序返回总销售额。仅考虑 @target_date 参数之前完整六个月内发生的销售情况。”

数据库中存在 3 个表。
销售人员(SalesPersonID,SalesYTD)
SalesOrderHeader (SalesOrderID,OrderDate,ShipDate)
SalesOrderDetail (SalesOrderID,SalesOrderDetailID,OrderQty,ProductID,UnitPrice)

这就是我目前所处的位置。我需要将我所掌握的内容汇编成一份声明并进行必要的修改。请帮忙!

要获取按单位计算的前 5 名最高销售额，应使用以下语法:

SELECT 
    ProductID, 
    SUM(Orderqty*Unitprice)   
FROM SalesOrderDetail  
GROUP BY ProductID  
WHERE Orderqty >=1 
  AND COUNT(productID) =5  
ORDER BY SUM(Orderqty*Unitprice) DESC  
LIMIT 5; 

对于 target_date 参数，我认为它会是这样的？

SELECT 
    SalespersonID AS ‘Sales Representative’, 
    SalesYTD AS ‘Total Sales’, target_date  
FROM Salesperson  
WHERE target_date BETWEEN ‘01-DEC-13’ AND ’01-May-14’;  

Answer 1

对于销售额最高的前五名，我宁愿建议稍微简化的

select productid, sum(orderqty * unitprice) as sales
from salesorderdetail
group by productid
order by sales desc
limit 5

在@target_date之前的六个月，类似

where orderdate between date_sub(@target_date, interval 6 months) and @target_date

<小时/>

假设有一个 FK SalesOrderDetail(SalesPersonID)，您可以将表和前五名销售额连接为

select p.*
from salesperson p
join salesorderheader h on h.salespersionid = p.salespersionid
join salesorderdetail d on d.salesorderid = h.salesorderid
join (select productid, sum(orderqty * unitprice) as sales
      from salesorderdetail
      group by productid
      order by sales desc
      limit 5) t5 on t5.productid = d.productid
where h.orderdate between date_sub(@target_date, interval 6 months) and @target_date
order by p.salesytd desc