<?php
include ('config.php');
$connection = mysql_connect($mysql_host, $mysql_user, $mysql_password);
$db = mysql_select_db($mysql_database, $connection);
$machinename = $_POST['machinename'];
$safemachinename = mysql_real_escape_string($machinename);
$query = mysql_query("delete from Notification where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Keystrokes where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Clipboard where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Passwords where machinename=$safemachinename", $connection);
foreach($_POST['checkbox'] as $checkbox){
$query = mysql_query("TRUNCATE TABLE $checkbox", $connection);
}
?>
我收到错误“为 foreach() 提供的参数无效。是因为我在测试时没有检查任何复选框吗?
这看起来正确吗?
if(isset($_POST['checkbox'])) {
foreach($_POST['checkbox'] as $checkbox){
$query = mysql_query("TRUNCATE TABLE $checkbox", $connection);
}
}
这是复选框
<form method="post" name="checkDelete" id="checkDelete" action="deletelogs.php">
<label class="checkbox-inline">
<input type="checkbox" name="Notifications"/> Notifications</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="Keystrokes"/> Keystrokes</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="Passwords"/> Passwords</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="Clipboard"/> Clipboard Records</label><br><br>
<button type="submit" class="btn btn-primary">Delete Logs</button>
</form>
基本上,您可以使用复选框选择要删除的表。这是用于客户端管理程序的。
好吧,到目前为止一切顺利。这似乎并没有删除任何内容:
<form method="post" name="formdelete" id="formdelete" action="deletelogs.php">
<div class="form-group">
<label>Delete all logs where computer name is</label><input class="form-control" width = "200px" placeholder="Please input machine name here..." /><br>
<br>
<center><input type="submit" name="btnDelete" class="btn btn-primary" value="Delete now"></center>
</form>
$machinename = $_POST['machinename'];
$safemachinename = mysql_real_escape_string($machinename);
$query = mysql_query("delete from Notification where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Keystrokes where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Clipboard where machinename=$safemachinename", $connection);
$query = mysql_query("delete from Passwords where machinename=$safemachinename", $connection);
最佳答案
您的 html 部分有错误。像这样使用
<form method="post" name="checkDelete" id="checkDelete" action="">
<label class="checkbox-inline">
<input type="checkbox" name="checkbox[]" value="Notifications"/> Notifications</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="checkbox[]" value="Keystrokes"/> Keystrokes</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="checkbox[]" value="Passwords"/> Passwords</label><br>
<label class="checkbox-inline">
<input type="checkbox" name="checkbox[]" value="Clipboard"/> Clipboard Records</label><br><br>
<button type="submit" class="btn btn-primary">Delete Logs</button>
</form>
关于php - 这个 foreach 语句有什么问题?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29202659/