我正在尝试将多行合并为具有多列的单独行,其中数据来自三个表。我遵循了MySQL pivot table中的建议但问题和答案不考虑多重连接。
以下是基础表格:
table n
+------+----+------+
| name | id | code |
+------+----+------+
| foo | 1 | NULL |
| bar | 2 | z |
| baz | 3 | y |
+------+----+------+
table ac
+------+----+
| code | id |
+------+----+
| h | 1 |
| i | 2 |
+------+----+
table c
+-----+------+-------+
| cid | code | desc |
+-----+------+-------+
| 9 | h | desch |
| 9 | i | desci |
| 8 | z | descz |
| 8 | y | descy |
+-----+------+-------+
以下是预期结果:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| foo | null | desch |
| bar | descz | desci |
| baz | descy | null |
+------+-------+-------+
我可以通过以下方式获得非常接近我想要的结果:
select
n.name,
n.code as type8,
ac.code as type9
from n
left join ac
on ac.id=n.id
但正如预期的那样,这仅产生代码:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| foo | null | h |
| bar | z | i |
| baz | y | null |
+------+-------+-------+
我有兴趣用表 c 中的较长描述替换代码。
最佳答案
第一步是使用 case
使用 pivot tables in mysql 中的技术从同一个表中的多行返回多列数据。 :
select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join c
on n.code=c.code
这会为 type8 产生正确的结果,但为 type9 产生空值:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| foo | null | null |
| bar | descz | null |
| baz | descy | null |
+------+-------+-------+
下一步是获取 type9 的结果:
select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join ac
on ac.id=n.id
left join c
on c.code=ac.code
这会产生:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| foo | null | desch |
| bar | null | desci |
| baz | null | null |
+------+-------+-------+
如果这两个结果用 联合在一起
select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join c
on n.code=c.code
union
select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join ac
on ac.id=n.id
left join c
on c.code=ac.code
行仍然需要合并:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| bar | descz | null |
| baz | descy | null |
| foo | null | null |
| foo | null | desch |
| bar | null | desci |
| baz | null | null |
+------+-------+-------+
最后,我通过使用removing nulls from a unioned query的聚合技术达到了预期的结果。 :
select
n.name,
min(type8), min(type9)
from
(select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join c
on n.code=c.code
union
select
n.name,
case when c.cid=8 then c.desc end as type8,
case when c.cid=9 then c.desc end as type9
from n
left join ac
on ac.id=n.id
left join c
on c.code=ac.code) as n
group by n.name
产生预期结果:
+------+-------+-------+
| name | type8 | type9 |
+------+-------+-------+
| foo | null | desch |
| bar | descz | desci |
| baz | descy | null |
+------+-------+-------+
关于mysql - 如何在mysql中通过多个表的多个连接来组合多行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56403019/