对于下表,是否可以创建 SQL 语句来创建数据矩阵或 View ?
表:
TeamA|TeamB|Won|Lost
--------------------
A | B | 5 | 3
A | C | 2 | 4
A | D | 9 | 1
B | E | 5 | 5
C | A | 2 | 4
结果矩阵:
| A | B | C | D | E
----------------------------
A | 0 | 2 | -2 | 8 | 0
B | 0 | 0 | 0 | 0 | 0
C | -2 | 0 | 0 | 0 | 0
最佳答案
有两种方法可以在 MySQL 中透视数据。如果您提前知道这些值(团队),那么您将对这些值进行硬编码,或者您可以使用准备好的语句来生成动态 sql。
静态版本是:
select TeamA,
max(case when TeamB = 'A' then won - lost else 0 end) as A,
max(case when TeamB = 'B' then won - lost else 0 end) as B,
max(case when TeamB = 'C' then won - lost else 0 end) as C,
max(case when TeamB = 'D' then won - lost else 0 end) as D,
max(case when TeamB = 'E' then won - lost else 0 end) as E
from yourtable
group by TeamA;
如果您想使用带有准备好的语句的动态版本,代码将为:
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'MAX(CASE WHEN TeamB = ''',
TeamB,
''' THEN won - lost else 0 END) AS `',
TeamB, '`'
)
) INTO @sql
from
(
select *
from yourtable
order by teamb
) x;
SET @sql
= CONCAT('SELECT TeamA, ', @sql, '
from yourtable
group by TeamA');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
编辑#1,考虑到这一点后,我实际上会做一些稍微不同的事情。我将生成一个真实的矩阵,其中团队出现在行和列中。为此,您首先需要使用 UNION ALL
查询来获取两列中的所有团队:
select teama Team1, teamb Team2,
won-lost Total
from yourtable
union all
select teamb, teama,
won-lost
from yourtable
参见SQL Fiddle with Demo 。完成后,您将透视数据:
select Team1,
coalesce(max(case when Team2 = 'A' then Total end), 0) as A,
coalesce(max(case when Team2 = 'B' then Total end), 0) as B,
coalesce(max(case when Team2 = 'C' then Total end), 0) as C,
coalesce(max(case when Team2 = 'D' then Total end), 0) as D,
coalesce(max(case when Team2 = 'E' then Total end), 0) as E
from
(
select teama Team1, teamb Team2,
won-lost Total
from yourtable
union all
select teamb, teama,
won-lost
from yourtable
) src
group by Team1;
参见SQL Fiddle with Demo 。这给出了更详细的结果:
| TEAM1 | A | B | C | D | E |
-------------------------------
| A | 0 | 2 | -2 | 8 | 0 |
| B | 2 | 0 | 0 | 0 | 0 |
| C | -2 | 0 | 0 | 0 | 0 |
| D | 8 | 0 | 0 | 0 | 0 |
| E | 0 | 0 | 0 | 0 | 0 |
关于mysql - SQL 语句 - SQL 矩阵,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14772882/