$result=("select * FROM blablabla ") ;
while($row = mysql_fetch_array($result))
{$another=("select * FROM blablabla ") ;
while($dow = mysql_fetch_array($another)){} }
这不起作用,请给我提示
最佳答案
您实际上并未运行查询:
$result=mysql_query("select * FROM blablabla ") ;
while($row = mysql_fetch_array($result))
{
// do stuff
}
Please, don't use mysql_*
functions in new code 。它们不再维护and are officially deprecated 。请参阅red box ?了解 prepared statements相反,并使用 PDO ,或MySQLi -this article将帮助您决定哪个。如果您选择 PDO,here is a good tutorial .
关于php - 当php获取表时再次获取同一个表,怎么可能?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14774325/