我有一个 select 语句试图从数据库中选择匹配项,但在获得结果后,匹配项是单词,而不是数字。
SELECT DATA ,
"CASE WHEN data LIKE '%one two%' THEN 2
ELSE CASE WHEN data LIKE '%one%' THEN 1
ELSE 0
END
END
END" AS 'matches'
FROM remember
LIMIT 0 , 30
结果:
列匹配:
"CASE WHEN data LIKE '%love%' THEN 2" ELSE CASE W...
"CASE WHEN data LIKE '%love%' THEN 2" ELSE CASE W...
"CASE WHEN data LIKE '%love%' THEN 2" ELSE CASE W...
预期结果:
列匹配:
2
1
0
最佳答案
您不需要多次使用 CASE:
SELECT CASE WHEN data LIKE '%one two%' THEN 2
WHEN data LIKE '%one%' THEN 1
ELSE 0
END AS 'matches'
关于php - 匹配以单词显示,而不是 mysql 中的数字,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33114941/