如何为以下元素编写正确的 Xpath 和 CSS - 快速查看。
网站上有多个快速查看按钮,但我正在尝试单击其中一个。
<button type="button" class="cta-button cta-button--small cta-button--quick-look cta-button--nordstromrack"><span class="cta-button__content">Quick Look<span class="cta-button__hidden-text">Nike - Club Crew Neck Sweater</span></span><img alt="spinner" src="data:image/png;base64,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" class="cta-button__spinner"></button>
<span class="cta-button__content">Quick Look<span class="cta-button__hidden-text">Nike - Club Crew Neck Sweater</span>
最佳答案
这是 xpath,如果您尝试单击“Nike - Club Crew New Sweater”快速查看按钮。
//span[.='Nike - Club Crew Neck Sweater']/ancestor::button
关于html - 如何为这个 HTML 编写 XPath 和 CSS?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55110824/