php - 样式化 PHP 回显表

标签 php css sql twitter-bootstrap

我终于弄清楚了如何使用 PHP 显示我的 SQL 表,但是我很难让样式显示出来。到目前为止,这是我所拥有的,关于如何设计 echo 的任何指示?什么都没有出现。我这样做是不是设计 echo 的不正确方式?我正在尝试使用 Bootstrap CSS 设置样式。

<html>
    <head>
        <title>Abacus PHP SQL Server Connection</title>
    </head>
    <body>
        <?php
            $db_host = '***';
            $db_user = '***';   //recommend using a lower privileged user
            $db_pwd = '***';
            $database = '***';
            $table = '***';

            $connectionInfo = array("UID" => $db_user, "PWD" => $db_pwd, "Database"=>$database); 
            $conn = sqlsrv_connect( $db_host, $connectionInfo);
            if( !$conn )
            {
                 echo "Connection could not be established.\n";
                 die( print_r( sqlsrv_errors(), true));
            }

            $tsql = "SELECT category, data_desc, data_source, update_cycle,ISNULL(datename(mm,last_abadata_update) + + ' ' + DATENAME(dd,last_abadata_update) + ', ' + DATENAME(yyyy, last_abadata_update),'') AS last_abadata_update, ISNULL(datename(mm,last_abadata2_update) + ' ' + DATENAME(dd,last_abadata2_update) + ', ' + DATENAME(yyyy,last_abadata2_update),'') AS last_abadata2_update FROM {$table} ORDER BY category, data_source, data_desc";
            $result = sqlsrv_query( $conn, $tsql);
            if (!$result) {
             die("Query to show fields from table failed");
            }

            echo "<table >";
            echo "<tr>";

            // printing table headers with desired column names
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Category";
            echo "</td>";
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Description";
            echo "</td>";
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Source";
            echo "</td>";
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Update Cycle";
            echo "</td>";
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Last AbaData Update";
            echo "</td>";
            echo "<td style='border=1px solid black;Font-size=18;Font-Weight=bold'>";
            echo "Last AbaData 2.0 Update";
            echo "</td>";
            echo "</tr>";

            while($row = sqlsrv_fetch_array($result))
            {
                echo "<tr>";
                echo "<td style='border=1px solid black'>";
                echo $row['category']; 
                echo "</td>";
                echo "<td style='border=1px solid black'>";
                echo $row['data_desc']; 
                echo "</td>";
                echo "<td style='border=1px solid black'>";
                echo $row['data_source']; 
                echo "</td>";
                echo "<td style='border=1px solid black'>";
                echo $row['update_cycle'];  
                echo "</td>";
                echo "<td style='border=1px solid black'>";
                echo $row['last_abadata_update'];  
                echo "</td>";
                echo "<td style='border=1px solid black'>";
                echo $row['last_abadata2_update'];  
                echo "</td>";
                echo "</tr>\n";
            }
            echo "</table>";

            sqlsrv_free_stmt( $result);
            sqlsrv_close( $conn);
            ?>
    </body>
</html>

最佳答案

CSS 接受 : 而不是 = 所以将 style='border=1px solid black' 更改为 style='border:1px纯黑色'.

关于php - 样式化 PHP 回显表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33943544/

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