mysql - 如何选择过去 30 天的数据并包含空行

Question

我想从数据库(表a_days、HrEmployee和HrAttLogsFormatted)获取最近1个月的出勤情况，无论数据库是否为空。当数据为空时，我想在有来自 LogsFormatted.DateIn 的显示数据时显示“-”，并且可以在 WHERE BETWEEN 和 (Y-m-d) 中 日期格式。 (示例从 2018-06-01 到 2018-06-10)

查询:

SELECT
    Employee.Id as "EmployeeId",
    Employee.Name as "Name",
    TheDay.Days as "Date",
    LogsFormatted.DateIn as "DateIn",
    LogsFormatted.ScanIn as "ScanIn"
FROM
    HrEmployee as Employee
    LEFT JOIN HrEmployeeShift as EmployeeShift ON Employee.ShiftId = EmployeeShift.Id
    LEFT JOIN HrAttMachine as Machine ON Employee.MachineIP = Machine.IP
    LEFT JOIN HrAttLogsFormatted as LogsFormatted ON LogsFormatted.FingerId = Employee.Id
    LEFT JOIN a_days as TheDay ON TheDay.Days = DATE_FORMAT(LogsFormatted.DateIn, "%d")
WHERE Employee.ShiftId = EmployeeShift.Id
AND Employee.Id = '14522228'
ORDER BY Employee.Id, Employee.Name, TheDay.Days, LogsFormatted.DateIn ASC

结果:

FingerId    Name                Date   DateIn        ScanIn
14522228    Aldan Rizki Santosa 3      2018-07-06    06:45:54
14522228    Aldan Rizki Santosa 4      2018-07-09    06:38:12
14522228    Aldan Rizki Santosa 5      2018-07-10    06:48:35

我想要什么:

FingerId    Name                Date   DateIn        ScanIn
14522228    Aldan Rizki Santosa 1      -             -
14522228    Aldan Rizki Santosa 2      -             -
14522228    Aldan Rizki Santosa 3      2018-07-06    06:45:54
14522228    Aldan Rizki Santosa 4      2018-07-09    06:38:12
14522228    Aldan Rizki Santosa 5      2018-07-10    06:48:35
14522228    Aldan Rizki Santosa 6      -             -
.....
..... 
..... Until the date at the end of the month

Answer 1

您可以尝试以下查询并检查吗？

<前>选择 员工详细信息.员工 ID ,员工详细信息.姓名 ,TheDay.rn AS Days ,员工详细信息.日期 ,EmployeeDetail.ScanIn 从 (SELECT TOP (DATEDIFF(DAY, '2018-01-01', DATEADD(MONTH,1,'2018-01-01'))) rn = ROW_NUMBER() OVER (ORDER BY s1.[object_id]) 来自 sys.all_objects AS s1 交叉连接 sys.all_objects AS s2 按 s1.[object_id] 排序 ) 当天外层申请 (选择 Employee.Id 作为 EmployeeId， Employee.Name 作为姓名， TheDay.rn 作为日期， LogsFormatted.DateIn 为“DateIn”， LogsFormatted.ScanIn 为“ScanIn” 来自 HrEmployee 作为员工 LEFT JOIN HrEmployeeShift as EmployeeShift ON Employee.ShiftId = EmployeeShift.Id 左连接 HrAttMachine 作为机器 ON Employee.MachineIP = Machine.IP LEFT JOIN HrAttLogsFormatted as LogsFormatted ON LogsFormatted.FingerId = Employee.Id WHERE LogsFormatted.DateIn = TheDay.rn) AS EmployeeDetail 哪里 EmployeeDetail.EmployeeId = '14522228' 按 EmployeeDetail.Id、EmployeeDetail.Name、TheDay.Days、EmployeeDetail.DateIn ASC 排序