mysql - 如何让这 2 个 SQL 查询返回 1 个结果集？ (他们选择相同的项目，但 where 子句不同)

Question

我想将此查询合并为一个，按日期返回 2 个值(“scount_atp”，其中 estado=1 和“scount_xxx”，其中 estado=4):

SELECT DATE_FORMAT(FROM_UNIXTIME(fecha),"%m-%d-%Y") as sdate, COUNT(id) as scount_atp FROM entradas WHERE estado = '1' AND fecha <= UNIX_TIMESTAMP(NOW()) AND fecha >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 1 YEAR)) GROUP BY sdate

SELECT DATE_FORMAT(FROM_UNIXTIME(fecha),"%m-%d-%Y") as sdate, COUNT(id) as scount_xxx FROM entradas WHERE estado = '4' AND fecha <= UNIX_TIMESTAMP(NOW()) AND fecha >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 1 YEAR)) GROUP BY sdate

我是 MySQL 的新手，如果这太基础了，我很抱歉......

谢谢大家的帮助!

Answer 1

SELECT 
  DATE_FORMAT(FROM_UNIXTIME(fecha),"%m-%d-%Y") as sdate, 
  SUM(IF(estado = '1',1,0)) as scount_atp,
  SUM(IF(estado = '4',1,0)) as scount_xxx
FROM entradas 
WHERE estado IN('1','4')
  AND fecha <= UNIX_TIMESTAMP(NOW()) 
  AND fecha >= UNIX_TIMESTAMP(DATE_SUB(NOW(), INTERVAL 1 YEAR)) 
GROUP BY sdate

让我在这里添加一个不相关的东西:如果 estado 列是 INT 类型，您可能想写 1 而不是 '1' - 或者您可能以全表扫描结束，将 int 列转换为字符串以进行比较。