mysql - 嵌套的 MySQL 查询

Question

我一直在尝试为公共(public)交通系统编写查询，当我输入起点站和终点站号码时，该系统会输出路线列表。

这是我的 MySQL 表:

mysql> desc route_timings;
+----------------+---------+------+-----+---------+----------------+
| Field          | Type    | Null | Key | Default | Extra          |
+----------------+---------+------+-----+---------+----------------+
| ID             | int(11) | NO   | PRI | NULL    | auto_increment |
| route_number   | int(11) | NO   |     | NULL    |                |
| stop_number    | int(11) | NO   |     | NULL    |                |
| arrival_time   | time    | YES  |     | NULL    |                |
| departure_time | time    | YES  |     | NULL    |                |
+----------------+---------+------+-----+---------+----------------+
5 rows in set (0.00 sec)

以下是示例值:

mysql> select * from route_timings;
+----+--------------+-------------+--------------+----------------+
| ID | route_number | stop_number | arrival_time | departure_time |
+----+--------------+-------------+--------------+----------------+
|  1 |           54 |           1 | 10:00:00     | 10:05:00       |
|  2 |           54 |           2 | 11:00:00     | 11:05:00       |
|  3 |           54 |           3 | 12:00:00     | 12:05:00       |
|  4 |           55 |           3 | 13:00:00     | 13:05:00       |
|  5 |           55 |           4 | 14:00:00     | 14:05:00       |
|  6 |           55 |           5 | 15:00:00     | 15:05:00       |
|  7 |           60 |           3 | 10:00:00     | 10:05:00       |
|  8 |           60 |           2 | 11:00:00     | 11:05:00       |
|  9 |           60 |           1 | 12:00:00     | 12:05:00       |
+----+--------------+-------------+--------------+----------------+
9 rows in set (0.01 sec)

我的问题是:如果我想列出包含 stop_number 1 和 stop_number 3 的 route_number，我会编写一个类似于此的查询:

SELECT DISTINCT `route_number` FROM `route_timings` WHERE `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=1
) AND `route_number` IN (
    SELECT `route_number` FROM `route_timings` WHERE `stop_number`=3
);

但是，上面的查询只会返回包含两个站点的 route_numbers，而不是源站点 (1) 在目标站点 (3) 之前到达的路线。

查询将返回以下内容:

+--------------+
| route_number |
+--------------+
|           54 |
|           60 |
+--------------+

route_number 60 不是从 1 开始到 3，而是从 3 开始到 1。有人可以帮我把那个位添加到查询中，以便查询只输出 route_numbers，其中 arrival_time 为 stop_number 1 小于 stop_number 3 的 arrival_time。

提前致谢。 -肖恩

Answer 1

怎么样:

select fromStop.RouteNumber  
from routeTimings fromStop  
  inner join routeTimings toStop on toStop.RouteNumber = fromStop.RouteNumber and toStop.StopNumber = 3 and toStop.ArrivalTime > fromStop.DepartureTime  
where fromStop.StopNumber = 1

请注意，这是根据我习惯的约定使用的 SQL 服务器语法和名称，但原则应该很清楚