我有以下 MySQL 查询/子查询:
SELECT id, user_id, another_id, myvalue, created, modified,
(
SELECT id
FROM users_values AS ParentUsersValue
WHERE ParentUsersValue.user_id = UsersValue.user_id
AND ParentUsersValue.another_id = UsersValue.another_id
AND ParentUsersValue.id < UsersValue.id
ORDER BY id DESC
LIMIT 1
) AS old_id
FROM users_values AS UsersValue
WHERE created >= '2009-12-20'
AND created <= '2010-01-21'
AND user_id = 9917
AND another_id = 23
鉴于列出的条件,子查询 (old_id) 的结果应该为空(在我的表中找不到匹配项)。 MySQL 没有返回 null,它似乎只是删除了“WHERE ParentUsersValue.user_id = UsersValue.user_id”子句并选择与其他两个字段匹配的第一个值。这是一个 MySQL 错误,还是由于某种原因这是预期的行为?
更新:
CREATE TABLE users_values (
id int(11) NOT NULL AUTO_INCREMENT,
user_id int(11) DEFAULT NULL,
another_id int(11) DEFAULT NULL,
myvalue double DEFAULT NULL,
created datetime DEFAULT NULL,
modified datetime DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=2801 DEFAULT CHARSET=latin1
EXPLAIN EXTENDED
:
id select_type table type possible_keys key key_len ref rows filtered Extra
1 PRIMARY UsersValue index_merge user_id,another_id user_id,another_id 5,5 NULL 1 100.00 Using intersect(user_id,another_id); Using where
2 DEPENDENT SUBQUERY ParentUsersValue index PRIMARY,user_id,another_id PRIMARY 4 NULL 1 100.00 Using where
EXPLAIN EXTENDED 警告 1003
:
select `mydb`.`UsersValue`.`id` AS `id`,`mydb`.`UsersValue`.`user_id` AS `user_id`,`mydb`.`UsersValue`.`another_id` AS `another_id`,`mydb`.`UsersValue`.`myvalue` AS `myvalue`,`mydb`.`UsersValue`.`created` AS `created`,`mydb`.`UsersValue`.`modified` AS `modified`,(select `mydb`.`ParentUsersValue`.`id` AS `id` from `mydb`.`users_values` `ParentUsersValue` where ((`mydb`.`ParentUsersValue`.`user_id` = `mydb`.`UsersValue`.`user_id`) and (`mydb`.`ParentUsersValue`.`another_id` = `mydb`.`UsersValue`.`another_id`) and (`mydb`.`ParentUsersValue`.`id` < `mydb`.`UsersValue`.`id`)) order by `mydb`.`ParentUsersValue`.`id` desc limit 1) AS `old_id` from `mydb`.`users_values` `UsersValue` where ((`mydb`.`UsersValue`.`another_id` = 23) and (`mydb`.`UsersValue`.`user_id` = 9917) and (`mydb`.`UsersValue`.`created` >= '2009-12-20') and (`mydb`.`UsersValue`.`created` <= '2010-01-21'))
最佳答案
这会为我返回正确的结果(NULL
):
CREATE TABLE users_values (id INT NOT NULL PRIMARY KEY, user_id INT NOT NULL, another_id INT NOT NULL, created DATETIME NOT NULL);
INSERT
INTO users_values VALUES (1, 9917, 23, '2010-01-01');
SELECT *,
(
SELECT id
FROM users_values AS ParentUsersValue
WHERE ParentUsersValue.user_id = UsersValue.user_id
AND ParentUsersValue.another_id = UsersValue.another_id
AND ParentUsersValue.id < UsersValue.id
ORDER BY id
DESC
LIMIT 1
) AS old_id
FROM users_values AS UsersValue
WHERE created >= '2009-12-20'
AND created <= '2010-01-21'
AND user_id = 9917
AND another_id = 23
你能运行这个查询吗:
SELECT COUNT(*)
FROM users_values AS UsersValue
WHERE user_id = 9917
AND another_id = 23
并确保它返回 1
?
请注意,您的子查询不会过滤 created
, 因此子查询可以返回主查询定义范围之外的值。
更新:
这绝对是 MySQL
中的错误.
最有可能的原因是为 UsersValues
选择的访问路径是index_intersect
.
这会从两个索引中选择适当的范围并构建它们的交集。
由于这个错误,依赖子查询在交集完成之前被评估,这就是为什么你得到的结果是正确的 another_id
但错了user_id
.
当你强制PRIMARY
时,你能检查问题是否仍然存在吗?扫描 UsersValues
:
SELECT *,
(
SELECT id
FROM users_values AS ParentUsersValue
WHERE ParentUsersValue.user_id = UsersValue.user_id
AND ParentUsersValue.another_id = UsersValue.another_id
AND ParentUsersValue.id < UsersValue.id
ORDER BY id
DESC
LIMIT 1
) AS old_id
FROM users_values AS UsersValue FORCE INDEX (PRIMARY)
WHERE created >= '2009-12-20'
AND created <= '2010-01-21'
AND user_id = 9917
AND another_id = 23
此外,对于此查询,您应该在 (user_id, another_id, id)
上创建一个复合索引而不是 user_id
上的两个不同索引和 another_id
.
创建索引并稍微重写查询:
SELECT *,
(
SELECT id
FROM users_values AS ParentUsersValue
WHERE ParentUsersValue.user_id = UsersValue.user_id
AND ParentUsersValue.another_id = UsersValue.another_id
AND ParentUsersValue.id < UsersValue.id
ORDER BY
user_id DESC, another_id DESC, id DESC
LIMIT 1
) AS old_id
FROM users_values AS UsersValue
WHERE created >= '2009-12-20'
AND created <= '2010-01-21'
AND user_id = 9917
AND another_id = 23
user_id DESC, another_id DESC
子句在逻辑上是多余的,但它们将使索引用于排序。
关于sql - MySQL 子查询返回不正确的结果?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2102043/