php - Mysql 查询不通过 JSON 发送响应

Question

所以我有这个问题，

$sql="SELECT c.first_name, a.id, a.name, a.current_value,a.end_date from psf_customer c,
        psf_auctions a join psf_customer_bids b ON a.id=b.auction_id where c.user_id =b.user_id
        and TIMESTAMP (b.timestamp, '00:00:02') >= '$now' order by b.timestamp DESC";

$now 这是一个具有以下日期的变量，(当前日期)

$now = date('Y-m-d H:i:s');

正在通过

执行

 $bids = $this->Db->addSQL($sql)->execute()->fetchArray();

并发送响应

return json_encode($bids);

但是当我尝试获得响应时，

 var data = JSON.parse(d);
              console.log(data); 

此控制台不打印任何内容，查询在数据库上运行良好。我怀疑变量 $now 需要以某种方式改变？

Answer 1

试试这个:

$sql="SELECT c.first_name, a.id, a.name, a.current_value,a.end_date from psf_customer c,
    psf_auctions a join psf_customer_bids b ON a.id=b.auction_id where c.user_id =b.user_id
    and TIMESTAMP (b.timestamp, '00:00:02') >= now() order by b.timestamp DESC";