我的 Json 是:
{
"Response": {
"Asset": [
{
"id": 2461,
"name": "TestAsset7771",
"model_name": "TestModel777",
"serial_number": "TestAsset7771",
"current_data": {
"timestamp": "",
"name": "Temperature",
"value": "?"
}
},
{
"id": 2448,
"model_id": 1229,
"name": "TestAsset777",
"model_name": "TestModel777",
"serial_number": "TestAsset777",
"current_data": {
"timestamp": "",
"name": "Temperature",
"value": "?"
}
}
]
}
}
我的代码是:
JSONObject outerObject = new JSONObject(jsonObj.toString());
JSONObject innerObject = outerObject.getJSONObject("Response");
JSONArray jsonArray = innerObject.getJSONArray("Asset");
for (int i = 0, size = jsonArray.length(); i < size; i++)
{
JSONObject objectInArray = jsonArray.getJSONObject(i);
String[] elementNames = JSONObject.getNames(objectInArray)
for (String elementName : elementNames)
{
String value = objectInArray.getString(elementName);
System.out.printf("name=%s, value=%s\n", elementName, value);
}
}
对于内部数组——即当前数据,我得到的值是:
name=current_data, value={"timestamp":"","name":"Temperature","value":"?"}
我如何放置另一个内部数组以便我可以获得值 “时间戳”:“”,“名称”:“温度”,“值”:“?”在单独的变量中而不是完整的 JSON
最佳答案
最好用Gson解析 JSON。无论如何,如果您决定按原样进行操作,请尝试:
你有这样一个类:
class CurrentData{
String name,timestamp,value;
void print(){
System.out.printf("name=%s, timestamp=%s, value=%s\n", name,timestamp, value);
}
}
现在,按如下方式更改您的 for 循环:
for (String elementName : elementNames)
{
if(!elementName.equals("current_data")){
String value = objectInArray.getString(elementName);
System.out.printf("name=%s, value=%s\n", elementName, value);
}
else{
CurrentData obj=new CurrentData();// You can use array of objects declaring outside the loop as your need
JSONObject curr_object=objectInArray.getJSONObject("current_data");
obj.name=curr_object.getString("name");
obj.timestamp=curr_object.getString("timestamp");
obj.value=curr_object.getString("value");
obj.print();
}
}
关于java - Java 中 JSONArray 迭代中的数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19686777/