mysql - 从 View 中的 SQL 子查询返回值列表

Question

我这里有四个表(Study、Publication、Location、Drugs)和一个由 Drugs 和 Study 之间的多对多关系引起的连接表。

我使用以下脚本创建了一个 View :

SELECT 
        `l`.`country` AS `country`,
        `l`.`latitude` AS `latitude`,
        `l`.`longitude` AS `longitude`,
        `l`.`region` AS `region`,
        `s`.`enrolment` AS `enrolment`,
        `s`.`diagnosis` AS `diagnosis`,
        `s`.`registry_ID` AS `registry_ID`,
        `s`.`status` AS `status`,
        `s`.`site_name` AS `site_name`,
        `s`.`study_no` AS `study_no`,
        `p`.`pub_year` AS `pub_year`,
        `p`.`URL` AS `url`,
        `p`.`authors` AS `authors`,
        `p`.`pubMedId` AS `pubMedId`,
        `p`.`pub_title` AS `pub_title`,
        `d`.`name` AS `name`
    FROM
        (((`VL`.`Location` `l`
        join `VL`.`Study` `s`)
        join `VL`.`Publication` `p`)
        join `VL`.`Drugs` `d`)
    WHERE
        ((`l`.`id` = `s`.`location_id`)
            and (`p`.`study_id` = `s`.`id`)
            and `d`.`id` in ((SELECT 
                `VL`.`Study_Drugs`.`drugses_id`
            FROM
                `VL`.`Study_Drugs`
            WHERE
                (`VL`.`Study_Drugs`.`studiesList_id` = `s`.`id`))))

现在，我需要的是让子查询为我提供可以在每项研究中找到的完整药物列表，这就是我单独执行此查询时发生的情况:

SELECT d.name
FROM VL.Drugs d
WHERE d.id IN(SELECT drugses_id
            FROM Study_Drugs
            WHERE studiesList_id = 'whatever id')

所以，问题是为什么它只返回查询的完整列表，而不是在用作 View 脚本一部分的同一查询中？

EDIT 以包含示例数据和希望的结果:

学习:

'2', 'Spleen', '70', NULL, 'KALA-AZAR MEDICAL RESEARCH CENTER, RAMBAG ROAD , MUZAFFARPUR,  BIHAR -842001, INDIA ', 'Published', '75', NULL, '68'

出版物:

'12', 'http://www.ncbi.nlm.nih.gov/pubmed/10897369', 'Sundar S, Gupta LB, Rastogi V, Agrawal G, Murray HW.', '10897369', 'Short-course, cost-effective drugs with amphotericin B-fat emulsion cures visceral leishmaniasis.', '2000', '2'

地点:

'68', 'India', '26.118589', '85.400719', 'India Subcontinent'

药物(单独做子查询时):

'Pentavalent Antimonial'
'Miltefosine'

因此，除了研究和出版中的一些不必要的字段外，我希望从我的 View 中获得所有这些信息。最终值(药物)由与研究 ID 相关的所有药物组成，我现在每行得到的结果如下:

'India', '26.118589', '85.400719', 'India Subcontinent', '70', 'Spleen', NULL, 'Published', 'KALA-AZAR MEDICAL RESEARCH CENTER, RAMBAG ROAD , MUZAFFARPUR,  BIHAR -842001, INDIA ', '75', '2000', 'http://www.ncbi.nlm.nih.gov/pubmed/10897369', 'Sundar S, Gupta LB, Rastogi V, Agrawal G, Murray HW.', '10897369', 'Short-course, cost-effective drugs with amphotericin B-fat emulsion cures visceral leishmaniasis.', 'Pentavalent Antimonial'

如您所见，最后一个值仅由列表中的第一个药物组成

Answer 1

我想你希望你的 View 看起来像这样

create view your_view
as
select s.*, d.* --explicit name that stuff
from        Location l
inner join  Study s on l.id = s.location_id
inner join  Study_Drugs sd on s.id = sd.study_id
inner join  Drugs d on d.id = sd.drugs_id
inner join  Publications p on s.id = p.study_id;


select * from your_view where study_id = 1; -- whatever id

我不确定您要这些出版物做什么。 请使用带有“内部联接”的"new"符号，而不是您使用的“where”子句。