我有一个表单，可以通过 php 文件上的按钮发送变量(id)，该文件应该采用该 ID， 连接到我的mysql数据库，并根据我的“id”获取数据“partecipanti”，将“partecipanti”的数字加1并更新数据库。 但它不起作用。 为什么？ 这是我的 eventi.php
<!DOCTYPE HTML>
<html lang="en-US">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<meta name="HandheldFriendly" content="True">
<meta name="MobileOptimized" content="320"/>
<meta name="apple-mobile-web-app-capable" content="yes">
<meta name="apple-mobile-web-app-status-bar-style" content="black">
<meta http-equiv="cleartype" content="on">
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0, user-scalable=no">
<script src="JS/jquery-1.11.1.js.js"></script> <!--PER EVENTI-->
<link rel="stylesheet" type="text/css" href="CSS/stile.css"> <!--PER EVENTI-->
<script src="JS/func.js"></script> <!--PER EVENTI-->
<?php include ("PHP/phpfiles.php");?> <!--PER EVENTI-->
<script src="JS/snap.js"></script> <!--TBAR-->
<link rel="stylesheet" type="text/css" href="CSS/demo.css"><!--TBAR-->
<link rel="stylesheet" type="text/css" href="CSS/snap.css"><!--TBAR-->
<title>Eventi</title>
</head>
<body>
<div class="snap-drawers">
<div class="snap-drawer snap-drawer-left">
<div>
<h5>Menu</h5>
<ul>
<li><a href="eventi.php">Eventi</a></li>
<li><a href="FACEBOOK_ALBUM/albums.php">Album foto eventi</a></li>
<li><a href="dragElement.html">Contatti</a></li>
<li><a href="rightDisabled.html">Credits</a></li>
</ul>
</div>
</div>
</div>
<div id="content" class="snap-content">
<div id="toolbar">
<a href="#" id="open-left"></a>
<h1>BPARTY</h1>
</div>
<br> <br>
<?
$DBhost = "localhost";
$DBuser = "bestparty";
$DBpass = "";
$DBName = "my_bestparty";
/* specifichiamo il nome della nostra tabella */
$table = "Dati";
/* Connettiamoci al database */
mysql_connect($DBhost,$DBuser,$DBpass) or die("Impossibile collegarsi al server");
@mysql_select_db("$DBName") or die("Impossibile connettersi al database $DBName");
/* impostiamo la query ORDINANDO IN ORDINE DECRESCENTE PER ID */
$numerofesta = $_GET['idfesta'];
$sqlquery = "SELECT * FROM $table WHERE ID = $numerofesta";
$result = mysql_query($sqlquery);
$number = mysql_num_rows($result);
/*assegnamo e stampiamo le variabili*/
$festa = mysql_result($result,$i,"festa");
$data = mysql_result($result,$i,"data");
$luogo = mysql_result($result,$i,"luogo");
$prezzo = mysql_result($result,$i,"prezzo");
$organizzatore = mysql_result($result,$i,"organizzatore");
$facebook = mysql_result($result,$i,"linkevento");
$listapr = mysql_result($result,$i,"listapr");
$dettagli = mysql_result($result,$i,"Dettagli");
$nonpartecipanti = mysql_result($result,$i,"nonpartecipanti");
$partecipanti = mysql_result($result,$i,"partecipanti");
$imageUrl = "../fotofeste/$organizzatore.png";
if (!$organizzatore){
$organizzatore = "nophoto";
}
echo"<img src='../fotofeste/$organizzatore.png?12345689' class=\"imamgineeventocompleta\"/>";
if (!$facebook) {
$facebook = "www.bparty.org";
}
?>
<div id="contenitore">
<div class="testievento"> <font color="#000000"><? echo"$festa" ?></font>
<div style="margin-top:13px;">
<table id="tabellaelenchi">
<tr>
<td> <font color="#DC3F42"><? echo"$prezzo"; ?></font> </td>
</tr>
<tr>
<td> <font color="#534F4F"><? echo"$luogo" ?></font> </td>
</tr>
<tr>
<td> <font color="#534F4F"><? echo"$data" ?></font> </td>
</tr>
<tr>
<td> <font color="#4B5998"><? echo"<a href='http://$facebook' class=\"testofacebook\">LINK EVENTO SU FACEBOOK</a>" ?></font> </td>
</tr>
<tr>
<td> <font color="#534F4F"><? echo"$dettagli" ?></font> <br> <br> <br> </td>
</tr>
</table>
<div id="parteciperai">
<form action="PHP/partecipero.php">
<button name="numerofesta" value="<? echo"$numerofesta" ?>" type="submit">PARTECIPERO</button>
</form>
</div>
<div id="footer"><a href="tel:+393334784355"><font size="+1">Info e Prevendite</font></a></div>
</div>
</div>
<script type="text/javascript">
var snapper = new Snap({
element: document.getElementById('content')
});
</script>
</body>
</html>
这是 php 文件
<?
$id = $_POST['numerofesta'];
$db = mysql_connect("localhost","bestparty","");
$table = "Dati";
if ($db == FALSE)
die ("Errore nella connessione. Verificare i parametri nel file config.inc.php");
mysql_select_db("my_bestparty", $db)
or die ("Errore nella selezione del database. Verificare i parametri nel file config.inc.php");
$sqlquery = "SELECT * FROM $table WHERE ID = $id";
$result = mysql_query($sqlquery);
$number = mysql_num_rows($result);
/*assegnamo e stampiamo le variabili*/
$partecipanti = mysql_result($result,$i,"partecipanti");
$partecipantinew = $partecipanti + 1;
$query="UPDATE `Dati` SET `partecipanti`='$partecipantinew' WHERE `ID`=$idfesta ";
echo"$id";
?>
最佳答案
就像@lolbas所说，改变:
<form action="PHP/partecipero.php">
至
<form action="PHP/partecipero.php" method="POST">
关于php从post中保存变量并更新数据库，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27877542/