我正在使用 TypeScript 编写一个利用 AWS SDK 的非常简单的服务。我的 Jest 单元测试正在通过,但覆盖率报告显示“return result.Items”行未被覆盖。谁能告诉这是为什么吗?这是 Jest 中的错误吗?
// service file
/**
* Gets an array of documents.
*/
function list(tableName) {
const params = {
TableName: tableName,
};
return docClient
.scan(params)
.promise()
.then((result) => {
return result.Items;
});
}
// test file
const stubAwsRequestWithFakeArrayReturn = () => {
return {
promise: () => {
return { then: () => ({ Items: 'fake-value' }) };
},
};
};
it(`should call docClient.scan() at least once`, () => {
const mockAwsCall = jest.fn().mockImplementation(stubAwsRequest);
aws.docClient.scan = mockAwsCall;
db.list('fake-table');
expect(mockAwsCall).toBeCalledTimes(1);
});
it(`should call docClient.scan() with the proper params`, () => {
const mockAwsCall = jest.fn().mockImplementation(stubAwsRequest);
aws.docClient.scan = mockAwsCall;
db.list('fake-table');
expect(mockAwsCall).toBeCalledWith({
TableName: 'fake-table',
});
});
it('should return result.Items out of result', async () => {
const mockAwsCall = jest
.fn()
.mockImplementation(stubAwsRequestWithFakeArrayReturn);
aws.docClient.get = mockAwsCall;
const returnValue = await db.get('fake-table', 'fake-id');
expect(returnValue).toEqual({ Items: 'fake-value' });
});
最佳答案
未覆盖的行是传递给 then
的成功回调。
您的模拟将 then
替换为不接受任何参数且仅返回对象的函数。代码中的回调会在测试期间传递给 then
模拟,但它不会调用回调,因此 Jest
会正确报告您的测试未涵盖该回调。
不要试图返回一个看起来像Promise
的模拟对象,只需从你的模拟返回一个实际解析的Promise
即可:
const stubAwsRequestWithFakeArrayReturn = () => ({
promise: () => Promise.resolve({ Items: 'fake-value' })
});
...这样then
仍将是实际的Promise.prototype.then
并且您的回调将按预期被调用。
您还应该等待
返回的Promise
,以确保在测试完成之前已调用回调:
it(`should call docClient.scan() at least once`, async () => {
const mockAwsCall = jest.fn().mockImplementation(stubAwsRequest);
aws.docClient.scan = mockAwsCall;
await db.list('fake-table'); // await the Promise
expect(mockAwsCall).toBeCalledTimes(1);
});
it(`should call docClient.scan() with the proper params`, async () => {
const mockAwsCall = jest.fn().mockImplementation(stubAwsRequest);
aws.docClient.scan = mockAwsCall;
await db.list('fake-table'); // await the Promise
expect(mockAwsCall).toBeCalledWith({
TableName: 'fake-table',
});
});
关于javascript - 如何在 JavaScript 中对 Promise 'then' 的结果进行单元测试?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54500259/