python - 如何将 datetime.date 对象转换为 time.struct_time 对象？

Question

我有一个 python 脚本，我需要比较两个日期。我有一个日期列表作为 time.struct_time 对象，我需要将其与几个 datetime.date 对象进行比较。

如何将 datetime.date 对象转换为 time.struct_time 对象？或者我可以直接使用它们进行比较吗？

Answer 1

尝试使用 date.timetuple() .来自 Python 文档:

Return a time.struct_time such as returned by time.localtime(). The hours, minutes and seconds are 0, and the DST flag is -1. d.timetuple() is equivalent to time.struct_time((d.year, d.month, d.day, 0, 0, 0, d.weekday(), yday, -1)), where yday = d.toordinal() - date(d.year, 1, 1).toordinal() + 1 is the day number within the current year starting with 1 for January 1st.