我有一个 jsp 页面，它接受用户名和密码，然后重定向到一个 servlet。下面是jsp代码，
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<meta name="description" content="">
<meta name="author" content="">
<title>DeliverMe</title>
<!-- Bootstrap Core CSS -->
<link href="css/bootstrap.min.css" rel="stylesheet">
<!-- Custom CSS -->
<link href="css/sb-admin.css" rel="stylesheet">
<!-- Custom Fonts -->
<link href="font-awesome-4.1.0/css/font-awesome.min.css" rel="stylesheet" type="text/css">
<!-- HTML5 Shim and Respond.js IE8 support of HTML5 elements and media queries -->
<!-- WARNING: Respond.js doesn't work if you view the page via file:// -->
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/libs/html5shiv/3.7.0/html5shiv.js"></script>
<script src="https://oss.maxcdn.com/libs/respond.js/1.4.2/respond.min.js"></script>
<![endif]-->
<!-- jQuery Version 1.11.0 -->
<script src="js/jquery-1.11.0.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#btn-login').click(function() {
var userName = $('#userName').val();
var password = $('#password').val();
var datastr='userName='+userName+'&password='+ password;
$.ajax({
url : 'LoginCheck',
data :datastr,
success : function(responseText) {
$('#ajaxGetUserServletResponse').text(responseText);
},
error:function(url){
window.location = url;
}
});
});
});
</script>
</head>
</head>
<body>
<div class="container">
<span style="color: #000099"><center><h2>DeliverMe Admin Panel</h2></center></span>
<div id="loginbox" style="margin-top:50px;" class="mainbox col-md-6 col-md-offset-3 col-sm-8 col-sm-offset-2">
<div class="panel panel-info" >
<div class="panel-heading">
<div class="panel-title">Sign In</div>
</div>
<div style="padding-top:30px" class="panel-body" >
<div style="display:none" id="login-alert" class="alert alert-danger col-sm-12"></div>
<form id="loginform" class="form-horizontal" role="form">
<div style="margin-bottom: 25px" class="input-group">
<span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
<input id="userName" type="text" class="form-control" placeholder="username or email">
</div>
<div style="margin-bottom: 25px" class="input-group">
<span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
<input id="password" type="password" class="form-control" name="password" placeholder="password">
</div>
<div style="margin-top:10px" class="form-group">
<!-- Button -->
<div class="col-sm- 12 controls">
<a id="btn-login" class="btn btn-success">Login</a>
</div>
</div>
<span id="ajaxGetUserServletResponse" style="color: red;"></span>
</form>
</div>
</div>
</div>
</div>
</body>
</html>
然后我的 servlet 检查用户名和密码，如果错误则给出错误文本，但如果为真则应该重定向到成功页面。但是没有效果。下面是 servlet 代码，
if(db.loginCheck(userName, password))
{
request.getRequestDispatcher("/main.jsp").forward(request, response);
}else
{
String greetings = "Invalid Username/Password";
response.setContentType("text/plain");
response.getWriter().write(greetings);
}
最佳答案
我找到了解决方案。我已经像这样更改了我的 servlet 的响应，
if(db.loginCheck(userName, password))
{
response.getWriter().write("1");
}else
{
greetings = "Invalid Username/Password";
response.setContentType("text/plain");
response.getWriter().write(greetings);
}
在我的 jsp 页面上我放了这个，
<script type="text/javascript">
$(document).ready(function() {
$('#btn-login').click(function() {
var userName = $('#userName').val();
var password = $('#password').val();
var datastr='userName='+userName+'&password='+ password;
$.ajax({
url : 'LoginCheck',
data :datastr,
success : function(responseText) {
if(responseText == "1"){
window.location.assign("/main.jsp");
}else{
$('#ajaxGetUserServletResponse').text(responseText);
}
},
});
});
});
</script>
关于java - 如何使用ajax通过servlet重定向到成功页面？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27315006/