我正在为 Arduino Uno 编程,但我陷入了一个 while 循环,因为我无法对某些传感器值进行计算。当我读取我的四个传感器值并比较前两个与后两个的比率时,无论值是什么,我都会得到 0.00。这是我的代码:
while ( ( (frontleft + frontright) / (backleft + backright) <= 0.8 ) || ( (frontleft + frontright) / (backleft + backright) > 1.2) ) {
if (backleft + backright > frontleft + frontright) {
myStepper2.step(10);
}
if (backleft + backright < frontleft + frontright) {
myStepper2.step(-10);
}
int backleft = analogRead(A0);
int backright = analogRead(A1);
int frontleft = analogRead(A2);
int frontright = analogRead(A3);
Serial.print("Backleft Reading: ");
Serial.println(backleft);
Serial.print("\n");
Serial.print("BackRight Reading: ");
Serial.println(backright);
Serial.print("\n");
Serial.print("Frontleft Reading: ");
Serial.println(frontleft);
Serial.print("\n");
Serial.print("Frontright Reading: ");
Serial.println(frontright);
Serial.print("\n");
float ratio = (frontleft + frontright) / (backleft + backright);
float math = (5 + 6) / (4 + 5);
Serial.print("Math: ");
Serial.println(math);
Serial.print("Ratio: ");
Serial.println(ratio);
Serial.print("\n");
delay(500);
}
我正在获取传感器 backleft
、backright
、frontleft
和 frontright
的值,但“ratio ' 总是出现 0.00。因此,我相信我陷入了循环。这里发生了什么?
此外,为了检查,我添加了“数学” float 作为快速计算,但我在串行监视器中得到的值为 1.00。为什么?应该是 1.222。
最佳答案
尝试
float ratio = (frontleft + frontright) / float((backleft + backright));
while ( ratio <= 0.8 || ratio > 1.2) {
//do your thing here
ratio = (frontleft + frontright) / float((backleft + backright));
}
然后当你尝试打印时
Serial.println(ratio, 4) //prints four decimal places
关于c++ - 模拟读数的计算出现错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33359198/