所以,我有一个问题:
我在 android 中执行 opencv,由于我用手机拍摄的图像分辨率非常高,我想将图像调整为较小的图像,获取轮廓并处理图像,然后在原始图像上创建边界矩形.为此,我需要缩放边界框以使其完全适合我的原始图像。我的代码在原始图像上处理和绘制边界框时效果很好,但是,如何进行缩放?这是代码 fragment :
Mat &image = *(Mat *) matAddrRgba;
//over here I should resize image and do the processing with the resized one, and in the end, scale everything back so I can draw the bounding box to the original
Rect bounding_rect;
Mat thr(image.rows, image.cols, CV_8UC1);
cvtColor(image, thr, CV_BGR2GRAY); //Convert to gray
threshold(thr, thr, 150, 255, THRESH_BINARY + THRESH_OTSU); //Threshold the gray
vector<vector<Point> > contours; // Vector for storing contour
vector<Vec4i> hierarchy;
RotatedRect rect;
findContours(thr, contours, hierarchy, CV_RETR_CCOMP,
CV_CHAIN_APPROX_SIMPLE); // Find the contours in the image
sort(contours.begin(), contours.end(),
compareContourAreas); //Store the index of largest contour
bounding_rect = boundingRect(contours[0]);
rect = minAreaRect(contours[0]);
// matrices we'll use
Mat rot_mat, rotated;
// get angle and size from the bounding box
float angle = rect.angle;
Size rect_size = rect.size;
if (rect.angle < -45.) {
angle += 90.0;
swap(rect_size.width, rect_size.height);
}
rot_mat = getRotationMatrix2D(rect.center, angle, 1);
warpAffine(image, rotated, rot_mat, image.size(), INTER_CUBIC);
image = rotated;
cvtColor(image, thr, CV_BGR2GRAY); //Convert to gray
threshold(thr, thr, 150, 255, THRESH_BINARY + THRESH_OTSU); //Threshold the gray
findContours(thr, contours, hierarchy, CV_RETR_CCOMP, CV_CHAIN_APPROX_SIMPLE);
sort(contours.begin(), contours.end(), compareContourAreas);
bounding_rect = boundingRect(contours[0]);
image = Mat(image, bounding_rect);
最佳答案
好的,那么,我将从这里开始:
Mat &img = (Mat ) matAddrRgba;
Mat image;
double thrA = 5;
resize(img, image, Size((int) (img.size().width / thrA), (int) (img.size().height / thrA)));
Rect bounding_rect;
Mat thr(image.rows, image.cols, CV_8UC1);
cvtColor(image, thr, CV_BGR2GRAY); //Convert to gray
threshold(thr, thr, 150, 255, THRESH_BINARY + THRESH_OTSU); //Threshold the gray
vector<vector<Point> > contours; // Vector for storing contour
vector<Vec4i> hierarchy;
RotatedRect rect;
findContours(thr, contours, hierarchy, CV_RETR_CCOMP,
CV_CHAIN_APPROX_SIMPLE); // Find the contours in the image
sort(contours.begin(), contours.end(),
compareContourAreas); //Store the index of largest contour
bounding_rect = boundingRect(contours[0]);
bounding_rect.width = (int) (bounding_rect.width * thrA);
bounding_rect.height = (int) (bounding_rect.height * thrA);
bounding_rect.x = (int) (bounding_rect.x * thrA);
bounding_rect.y = (int) (bounding_rect.y * thrA);
rectangle(img, bounding_rect, Scalar(0, 172, 236, 255), 3);
如您所见,您应该有一个比例尺,该比例尺应该乘以边界矩形的宽度、高度、x 和 y。您可以从中找出其余部分。
关于android - C++ Opencv 重新缩放边界矩形,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44291434/