<分区>
我是 C++ 的新手。从示例中，我发现使用 sizeof 来检索数组的长度
int main()
{
int newdens[10];
// the first line returns 10 which is correct
std::cout << "\nLength of array = " << (sizeof(v1)/sizeof(*v1)) << std::endl;
std::cout << "\nLength of array = " << (sizeof(v1) << std::endl; //returns 40
std::cout << "\nLength of array = " << (sizeof(*v1)) << std::endl; //returns 4
}
但是如果我写一个这样的函数
#include <iostream>
void myCounter(int v1[])
{
int L, L2, L3;
L = (sizeof(v1)/sizeof(*v1));
L2 = (sizeof(v1));
L3 = (sizeof(*v1));
std::cout << "\nLength of array = " << L << std::endl;
std::cout << "\nLength of array = " << L2 << std::endl;
std::cout << "\nLength of array = " << L3 << std::endl;
}
int main()
{
int v1[10];
std::cout << "\nLength of array = " << (sizeof(v1)/sizeof(*v1)) << std::endl;
std::cout << "\nLength of array = " << (sizeof(v1)) << std::endl;
std::cout << "\nLength of array = " << (sizeof(*v1)) << std::endl;
myCounter(v1);
}
输出是L=2, L2 = 8, L3 = 4。我不明白问题出在哪里。
如何在函数中获取 v1 的正确长度？