我想将网页转换为 leet (1337) speak with XPath 和 PHP。
它可以仅使用 PHP 来完成，但随后 HTML 节点也被 leet speak 替换。
示例($html 是网页):
$find = array("a","b","c","d","e","f","g","h","i","j"."k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");
$repl = array("4","b","c","d","3","f","g","h","1","j","k","1","m","n","0","p","9","r","5","7","u","v","w","x","y","2");
$html = str_replace($find, $repl, $html);
这也替换了 HTML 节点。
这可以通过 XPath 和 PHP 使用 XPath 选择器 text() 完成吗？示例($html 是网页):
$dom = new DOMDocument();
$dom->loadHTML($html);
$xpath = new DOMXPath($dom);
$xpath->query('//text()');
\\HERE THE REPLACING IN XPATH
最佳答案
试试这个:
$dom = new DOMDocument;
$dom->loadHTML( $html );
$xpath = new DOMXPath( $dom );
$nodes = $xpath->query( '//text()' );
foreach( $nodes as $node )
{
$node->nodeValue = str_replace( $find, $repl, $node->nodeValue );
}
echo $dom->saveHTML();
请注意，这可能是满足您需求的更有用的 xpath 查询:
$nodes = $xpath->query( '//head/title/text() | //body//text()' );
... 因为这只会替换 <head><title> 中的文本或文本是 <body> 的后代.可能不想替换可能的样式、Javascript 和您拥有的东西。 ;-)
旁注:我已经用您的查找和替换字符数组对此进行了测试，但是它们有些可疑，我无法弄清楚。替换字符似乎并不总是与找到的字符对齐。我不知道为什么会这样。
我重新创建了数组，这些对我有用:
$find = array('a','b','c','d','e','f','g','h','i','j'.'k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z');
$repl = array('4','b','c','d','3','f','g','h','1','j'.'k','1','m','n','0','p','9','r','5','7','u','v','w','x','y','2');
我只是想不通为什么您的数组对我来说不有效。 :-/也许是编码问题？如果有人想插话并冒险猜测一下，请这样做。
编辑:正如 rxdazn 注意到的那样，"j"."k"是第一个数组中的问题，正如您从我重新创建的数组中看到的那样，我完全忽略了它(我将 $find 复制到 $repl，替换了引号，并填充了 leet 字符)。
关于php - 将 HTML 文本转换为 Leet (1337) Speak with XPath，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13532025/