我有一个 XML 文件 record.xml,它看起来像:
<record>
<name>john</name>
<gender>male</gender>
<subject>mathematics, english, science</subject>
</record>
<record>
<name>jamie</name>
<gender>female</gender>
<subject>mathematics, science</subject>
</record>
<record>
<name>jack</name>
<gender>male</gender>
<subject>social-science, english</subject>
</record>
我想编写一个 xpath 查询,它将返回 <record>
的所有子节点名称以及关联数组中所有这些子节点的值。
For Ex.:
For above XML file Output array should be-
array{ [0] => array{ [name] = 'john', [gender] = 'male', [subject] = 'mathematics, english, science' } [1] => array{ [name] = 'jamie', [gender] = 'female', [subject] = 'mathematics, science' } [2] => array{ [name] = 'jack', [gender] = 'male', [subject] = 'social-science, english' } }
下面是我写的部分代码返回所有<record>
子节点值而不是它们的节点名称。
.......
.......
$xmldoc = new DOMDocument();
$xmldoc->load('record.xml');
$xpathvar = new Domxpath($xmldoc);
$res = $xpathvar->query('//record');
foreach($res as $data){
//$data do not contain node values
$arr[] = $data->textContent;
}
//process $arr to get required format
.....
.....
我只想要一个 Xpath 查询,它将返回子节点名称及其值。
最佳答案
问题是记录,因为节点只是节点层次结构的一部分。您得到的是所有记录,但是您还想下降并从记录的子节点获取数据。一个非常具体的例子是:
<?php
$xmldoc = new DOMDocument();
$xmldoc->load('record.xml');
$xpathvar = new Domxpath($xmldoc);
$res = $xpathvar->query('//record');
foreach($res as $data){
$narr = [];
foreach ($data->childNodes as $cnode) {
$narr[$cnode->nodeName] = $cnode->nodeValue;
}
$arr[] = $narr;
}
print_r($arr);
应该输出如下内容:
Array
(
[0] => Array
(
[name] => john
[gender] => male
[subject] => mathematics, english, science
)
[1] => Array
(
[name] => jamie
[gender] => female
[subject] => mathematics, science
)
[2] => Array
(
[name] => jack
[gender] => male
[subject] => social-science, english
)
)
注意:此解决方案非常具体,如果您有额外的嵌套层次结构(我建议您这样做以存储多个主题),则可能会中断。
关于PHP + XPath 查询获取子节点及其值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37973058/