c++ - 将数据的某些部分从 const char * 数组复制到另一个 const char * 数组

Question

我能够在循环中将一些数据从 char 数组复制到另一个 char 数组。例如，我想将 char 数组的每 2 个字符提取并显示到 b 中。但它不适用于 const char *。谁能告诉我为什么它不能与 const char * 一起使用。实际上，我需要用 const char* 来做到这一点。

char array[] = "HelloRamBilasj";

cout << "total length of array buffer:" << strlen(array) << endl << endl;
int totalGoLength= strlen(array)/2 ; //divide by number of elements you want to display in one loop

cout << "required length of alice buffer:" << totalGoLength << endl << endl;

int oneGoCount=1;
int start=0;//starting index to copy
int next=2;//end index to copy

while( oneGoCount <= totalGoLength) {

    char *b = new char[100];
    // now copy the elemet into b.
    std::copy(array+start, array+next, b);

    for (int i = 0; i < 2; ++i){
        cout<< "the value of b is"<<b[i]<<endl;

    }
    cout<<endl<<endl;

    delete [] b;//erase the contents of b.
    start=start+2;//increment the next index
    next=next+2;//increment the next index

    oneGoCount=oneGoCount+1;

}//end of while

Answer 1

您不能更改 const char* 指向的数据，因为它指向的数据是 const。