python - 检查路径中是否存在某个文件夹

Question

我正在迭代文件夹并逐行读取文件以找到一些子字符串。

问题是我想在搜索过程中忽略某些文件夹(例如 bin 或 build)。

我尝试添加检查 - 但它仍然将其包含在搜索中

def step(ext, dirname, names):
    for name in names:
        if name.lower().endswith(".xml") or name.lower().endswith(".properties") or name.lower().endswith(".java"):
            path = os.path.join(dirname, name)
            if not "\bin\"" in path and not "\build" in path:
                with open(path, "r") as lines:
                    print "File: {}".format(path)
                    i = 0
                    for line in lines:
                        m = re.search(r"\{[^:]*:[^\}]*\}", line)
                        with open("search-result.txt", "a") as output:
                            if m is not None:
                                output.write("Path: {0}; \n    Line number: {1}; \n        String: {2}\n".format(path, i, m.group()))
                        i+=1

Answer 1

我怀疑您的条件失败，因为 \b 被解释为退格字符，而不是反斜杠字符后跟“b”字符。另外，看起来您在 bin 末尾转义了引号；这是故意的吗？

尝试转义反斜杠。

if not "\\bin\\" in path and not "\\build" in path: