c# - 如何访问动态按钮的事件处理程序？ Visual Studio 2015 WPF

Question

我正在尝试再次学习 C#，我想知道实现所需结果的方法是什么，这是我的代码，它会在我单击按钮时创建标签和按钮。

    private void button_Copy_Click(object sender, RoutedEventArgs e)
    {
        counter++;

        Label lbl = new Label();
        lbl.Content = counter.ToString();
        lbl.HorizontalAlignment = HorizontalAlignment.Center;
        lbl.VerticalAlignment = VerticalAlignment.Center;
        lbl.FontSize = 50;

        Button bt = new Button();
        bt.Content = "X";
        bt.HorizontalAlignment = HorizontalAlignment.Right;
        bt.VerticalAlignment = VerticalAlignment.Top;

        grid.Children.Add(lbl);
        grid.Children.Add(bt);
    }

但是，由于点击事件是动态创建的，因此我在确定将点击事件放在哪里时遇到了问题。我想要发生的是当我点击 X 按钮时，它会删除我点击的特定标签和 x 按钮。因此，如果我单击主按钮两次，它将在左上角显示一个带有 x 的 1，在左上角显示一个带有 x 的 2，当我单击 2 的 x 时，它将同时删除带有 2 和 x 的标签2 的按钮。

Answer 1

只需向按钮添加一个事件处理程序:

private void button_Copy_Click(object sender, RoutedEventArgs e)
{
    counter++;

    Label lbl = new Label();
    lbl.Content = counter.ToString();
    lbl.HorizontalAlignment = HorizontalAlignment.Center;
    lbl.VerticalAlignment = VerticalAlignment.Center;
    lbl.FontSize = 50;

    Button bt = new Button();
    bt.Content = "X";
    bt.HorizontalAlignment = HorizontalAlignment.Right;
    bt.VerticalAlignment = VerticalAlignment.Top;

    // add subscriber
    bt.Click += Button_Click;

    grid.Children.Add(lbl);
    grid.Children.Add(bt);
}

// On click event for button
private void Button_Click(object sender, EventArgs e) 
{
    // do whatever when button is clicked

    // this is a reference to the button that was clicked,
    // you can delete it here or do whatever with it
    Button buttonClicked = (Button)sender;
}

现在，当按钮被点击时，“Button_Click”将被触发。