我想每隔几秒更换一次图片，这是我的代码:
<?xml version = "1.0" encoding = "utf-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns = "http://www.w3.org/1999/xhtml">
<head>
<title>change picture</title>
<script type = "text/javascript">
function changeImage()
{
var img = document.getElementById("img");
img.src = images[x];
x++;
if(x >= images.length){
x = 0;
}
var timerid = setInterval(changeImage(), 1000);
} }
var images = [], x = 0;
images[0] = "image1.jpg";
images[1] = "image2.jpg";
images[2] = "image3.jpg";
</script>
</head>
<body onload = "changeImage()">
<img id="img" src="startpicture.jpg">
</body>
</html>
我的问题是它卡在了第一张图片上!
我也想尝试使用上一个和下一个按钮翻阅图片，但我不知道该怎么做。
最佳答案
正如我在评论中发布的那样，您不需要同时使用 setTimeout() 和 setInterval()，而且您也有语法错误(一个额外的})。像这样更正您的代码:
(编辑添加两个函数以强制显示下一张/上一张图像)
<!DOCTYPE html>
<html>
<head>
<title>change picture</title>
<script type = "text/javascript">
function displayNextImage() {
x = (x === images.length - 1) ? 0 : x + 1;
document.getElementById("img").src = images[x];
}
function displayPreviousImage() {
x = (x <= 0) ? images.length - 1 : x - 1;
document.getElementById("img").src = images[x];
}
function startTimer() {
setInterval(displayNextImage, 3000);
}
var images = [], x = -1;
images[0] = "image1.jpg";
images[1] = "image2.jpg";
images[2] = "image3.jpg";
</script>
</head>
<body onload = "startTimer()">
<img id="img" src="startpicture.jpg"/>
<button type="button" onclick="displayPreviousImage()">Previous</button>
<button type="button" onclick="displayNextImage()">Next</button>
</body>
</html>
关于javascript - 每隔几秒更改 HTML 页面中的图像，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13975891/