java - 如何读取xlink :label value using XPath

Question

我需要从 XML 中获取 xlink:label 值 (ASSET_1)。

<MESSAGE xmlns:xlink="http://www.w3.org/1999/xlink">
<ABOUT_VERSIONS>
<ABOUT_VERSION SequenceNumber="1"  xlink:label="ASSET_1" >
<CreatedDatetime>2015-08-24T09:30:47Z</CreatedDatetime>
<DataVersionName>Purchase Example</DataVersionName>
</ABOUT_VERSION>
</ABOUT_VERSIONS>
</MESSAGE>

我正在尝试的 Java 代码如下所示

XPathFactory xpf = XPathFactory.newInstance();            
XPath xPath = xpf.newXPath();

XPathExpression pathExpression = xPath.compile("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION");   
InputSource inputSource = new InputSource("C:/Sample.xml");  
NodeList Nodes = (NodeList) xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION", inputSource, XPathConstants.NODESET);

System.out.println("SequenceNumber:: "+xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION/@SequenceNumber", inputSource, XPathConstants.NODE));
System.out.println(" "+xPath.evaluate("MESSAGE/ABOUT_VERSIONS/ABOUT_VERSION/@xlink:label", inputSource, XPathConstants.NODE));

OutPut
SequenceNumber:: SequenceNumber="1"

null

我在提取 xlink:label 的值时犯了什么错误？请帮忙。

Answer 1

您可以使用 @*[name()='xlink:label'] 代替 @xlink:label。 也切换到 @*[local-name()='label'] 应该可以解决问题。