java - 如何在JPA中使用Plural Attributes进行条件查询?

标签 java sql hibernate jpa criteria

这是我要从中生成查询的根实体 ArticleType。我想获取一个集合 articleTypeVarianteOptionCollection 并为该集合添加一些条件。

public class ArticleType extends BaseEntity implements Serializable
{
    private static final long                   serialVersionUID    = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "art_typ_index")
    private Integer                             artTypIndex;
    @Column(name = "art_typ_code", nullable = false)
    private String                              artTypCode;
    @OneToMany(mappedBy = "atvoIndexArticleType", fetch = FetchType.LAZY)
    private Set<ArticleTypeVarianteOption>      articleTypeVarianteOptionCollection;

    public Integer getArtTypIndex()
    {
        return artTypIndex;
    }

    public void setArtTypIndex(Integer artTypIndex)
    {
        this.artTypIndex = artTypIndex;
    }


    public String getArtTypCode()
    {
        return artTypCode;
    }

    public void setArtTypCode(String artTypCode)
    {
        this.artTypCode = artTypCode;
    }


    @XmlTransient
    public Set<ArticleTypeVarianteOption> getArticleTypeVarianteOptionCollection()
    {
        return articleTypeVarianteOptionCollection;
    }

    public void setArticleTypeVarianteOptionCollection(Set<ArticleTypeVarianteOption> articleTypeVarianteOptionCollection)
    {
        this.articleTypeVarianteOptionCollection = articleTypeVarianteOptionCollection;
    }


}

这是我的 OptionArticle 实体:

public class ArticleTypeOption extends BaseEntity implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id 
      @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "ato_index")
    private Integer atoIndex;

    @Column(name = "ato_isremoved")
    private Integer atoIsremoved;
    @JoinColumn(name = "ato_index_art_type", referencedColumnName = "art_typ_index")
    @ManyToOne(fetch = FetchType.LAZY)
    private ArticleType atoIndexArtType;
    @JoinColumn(name = "ato_index_option", referencedColumnName = "opt_art_index")
    @ManyToOne(fetch = FetchType.LAZY)
    private OptionArticle atoIndexOption;

    public ArticleTypeOption() {
    }

    public ArticleTypeOption(Integer atoIndex) {
        this.atoIndex = atoIndex;
    }

    public Integer getAtoIndex() {
        return atoIndex;
    }

    public void setAtoIndex(Integer atoIndex) {
        this.atoIndex = atoIndex;
    }


    public Integer getAtoIsremoved() {
        return atoIsremoved;
    }

    public void setAtoIsremoved(Integer atoIsremoved) {
        this.atoIsremoved = atoIsremoved;
    }

    public ArticleType getAtoIndexArtType() {
        return atoIndexArtType;
    }

    public void setAtoIndexArtType(ArticleType atoIndexArtType) {
        this.atoIndexArtType = atoIndexArtType;
    }

    public OptionArticle getAtoIndexOption() {
        return atoIndexOption;
    }

    public void setAtoIndexOption(OptionArticle atoIndexOption) {
        this.atoIndexOption = atoIndexOption;
    }
}

我的查询是:

SELECT 
articleType
FROM ArticleType articleType 
LEFT JOIN articleType.articleTypeVarianteOptionCollection atOption
where atOption.atoIsremoved = 0;

我已经在 jpa 的 where 子句中尝试过这个:-

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<T> criteriaQry = criteriaBuilder.createQuery(entityClass);
Root<T> root = criteriaQry.from(entityClass);
criteriaQry.select(root).distinct(true);

for (PluralAttribute<? super T, ?, ?> pa : root.getModel().getPluralAttributes())
{
    System.out.println(pa.getName());
    System.out.println(pa.getCollectionType());
}

现在如何使用此 PluralAttribute 添加 where 子句?
提前致谢。

最佳答案

首先,让我们从 SQL 查询开始:

SELECT 
articleType
FROM ArticleType articleType 
LEFT JOIN articleType.articleTypeVarianteOptionCollection atOption
where atOption.atoIsremoved = 0;

每当您在 WHERE 条件中使用 LEFT JOIN 表时,JOIN 的行为将类似于 INNER JOIN

因此,这就是将此 SQL 查询转换为 Criteria 的方式:

Integer atoIsremoved = ...;

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<ArticleType> criteria = criteriaBuilder.createQuery(ArticleType.class);

Root<ArticleType> root = criteria.from(ArticleType.class);
criteria.select(root).distinct(true);

Join<ArticleType, ArticleTypeVarianteOption> joinOptions = root.join(
    "articleTypeVarianteOptionCollection", 
    JoinType.LEFT
);

criteria.where(
    criteriaBuilder.or(
        criteriaBuilder.isNull(
           joinOptions.get("id")
        ), 
        criteriaBuilder.equal(
            joinOptions.get("atoIsremoved"), atoIsremoved
        )
    )
);

TypedQuery<ArticleType> query = entityManager.createQuery(criteria);
List<ArticleType> resultList = query.getResultList();

关于java - 如何在JPA中使用Plural Attributes进行条件查询?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27957086/

相关文章:

java - 为什么 hibernate 不在 OneToMany 的所有者端设置外键

java - 使用 java 从 aws 获取主题 ARN

mysql - 如果确实加 1,则检查记录是否存在

java - hibernate 错误 - QuerySyntaxException : users is not mapped [from users]

php - 使用内连接从多个表中删除

sql - MySQL 查询在逗号分隔的字符串中查找值

java - 如何在 hibernate 中添加一对多关系?

java - ./* 和 ./* 之间有什么区别? :./* 在 java 类路径中

JavaFx - TextField.setText() 抛出 nullpointerException

java - 获取 cmd 中输入的文件名