我正在为 MIT OCW 类(class)做一些事情,它要求编写一个“图书馆”类(class)。现在我有这个:
#include <iostream>
using namespace std;
class Book{
string title;
bool rented;
public:
Book(string bookTitle){
title = bookTitle;
}
void borrowed(){
rented = true;
}
void returned(){
rented = false;
}
bool isBorrowed(){
return rented;
}
string getTitle(){
return title;
}
};
class Library{
string Lname;
Book bookList[100000000];
int numOfBooks = 0;
public:
Library(string name){
Lname = name;
}
void addBook(string bookName){
bookList[numOfBooks] = Book(bookName);
numOfBooks += 1;
}
void returnInfo(){
cout << "Library hours:" << "\n" << "Libraries are open daily from 9am to 5pm." << "\n" << "Library addresses:" << "\n" << "10 Main St." << "\n" << "228 Liberty St.";
}
};
int main()
{
Library l = Library("Hi");
return 0;
}
当我编译时,它给出了第 35 行没有匹配函数调用 'Book::Book()' 的错误。
最佳答案
编译器提示你没有为 Book 定义默认构造函数,你可以试试这个:
explicit Book(const string& bookTitle = std::string(""))
: title(bookTitle)
{
}
在堆栈上定义 100000000 导致溢出,
Book bookList[100000000];
尝试改用 vector
std::vector<Book> bookList;
在 addBook 中,您可以简单地使用 std::vector::push_back添加一本新书。要获得总书数,请使用 std::vector::size()
void addBook(const string& bookName){
bookList.push_back(Book(bookName));
}
建议:
- To pass parameter to function like std::string, pass by const
- reference is a better way. use member initialization list if possible
Library(const string& name) : Lname(name) { }
void addBook(const string& bookName){ }
关于c++ - 没有匹配函数调用 'Book::Book()',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16976367/