我不会撒谎。这是一个家庭作业问题。然而,就我而言,积分已经消失了。现在,我只是在寻找答案,因为我-认为-我可能疯了。
该程序的目标是执行命令ps -A | grep (输入字符串) | wc -l
的方式与 shell 的方式类似。因此,我生成进程,并让它们互相等待。最新的进程,即曾孙进程,execlp("ps","ps","-A",NULL)
它将自身替换为 ps -A
进程。在 execlp
之前,我确保其标准输出将发送到管道输出。下一个进程是 wait() ing,并且已经进行了自身设置,以便输入管道进入标准输入,标准输出进入输出管道,它将执行 grep,并且等等。
我几乎确信我已正确设置它。然而……程序确实如此。不是。工作。
#include <stdlib.h>
#include <iostream>
#include <string>
#define MAXLINE 1500
#define READ 0
#define WRITE 1
using namespace std;
int main( int argc, char** argv ) {
//* start of input block
if ( argc != 2 ) {
cout << "Usage: ./a.out arg1" << endl;
return 0;
}
string in = argv[1];
// end of input block */
int pipeA[2], pipeB[2], pid, stat;
// get our first set of pipes
if ( pipe(pipeA) < 0 ) {
cerr << "Pipe error.\n";
exit(-1);
}
if ( pipe(pipeB) < 0 ) {
cerr << "Pipe error.\n";
exit(-1);
}
// make the first fork
if ( (pid = fork() ) < 0 ) { cerr << "Fork error.\n"; exit(-1); }
if ( pid > 0 ) { // parent case
wait(&stat);
} else { // child case
if ( (pid = fork()) < 0 ) { cerr << "Fork Error\n"; exit(-1); }
if ( pid > 0 ) { // child
wait(&stat);
dup2(pipeA[READ],READ);
execlp("wc","wc","-l",NULL);
} else { // grand-child
if ( (pid = fork()) < 0 ) { cerr << "Fork Error\n"; exit(-1); }
if ( pid > 0 ) { // still grand-child
wait(&stat);
dup2(pipeB[READ],READ);
dup2(pipeA[WRITE],WRITE);
close(pipeB[READ]);
execlp("grep","grep",in.c_str(),NULL);
} else { // great grand-child
dup2(pipeB[WRITE],WRITE); // t now goes to pipeB[1]
close(READ);
close(pipeB[READ]);
execlp("ps", "ps", "-A", NULL);
}
}
}
return 0;
}
编辑:更改为我的代码的两管变体。
最佳答案
我几乎可以肯定这就是您想要做的事情。对于草率的编码提前表示歉意。现在有点晚了,我现在真的应该 sleep 了:
#include <iostream>
#include <string>
#include <cstdlib>
#include <cstdio>
#include <unistd.h>
#define READ 0
#define WRITE 1
// ps -A | grep argv[1] | wc -l
int main( int argc, char** argv )
{
// start of input block
if ( argc != 2 )
{
std::cout << "Usage: ./a.out arg1" << std::endl;
return 0;
}
// make local copy of argument
std::string in = argv[1];
int fd1[2], fd2[2], pid;
// allocate two pipe sets
if (pipe(fd1) < 0 || pipe(fd2) < 0)
{
perror("Failed to create pipe.");
return EXIT_FAILURE;
}
// launch first child process.
if ((pid = fork()) < 0)
{
perror("Failed to fork child(1)");
return EXIT_FAILURE;
}
if (pid == 0)
{
// wc -l process.
// stdin = fd2(read)
close(fd1[READ]);
close(fd1[WRITE]);
close(fd2[WRITE]);
dup2(fd2[READ],STDIN_FILENO);
execlp("wc","wc","-l",NULL);
}
// fork again. this time for grep
if ((pid = fork()) < 0)
{
perror("Failed to fork child(2)");
return EXIT_FAILURE;
}
if (pid == 0)
{
// grep argv[1] process.
// stdin = fd1(read)
// stdout = fd2(write)
close(fd1[WRITE]);
close(fd2[READ]);
dup2(fd2[WRITE], STDOUT_FILENO);
dup2(fd1[READ], STDIN_FILENO);
execlp("grep", "grep", in.c_str(), NULL);
}
// fork once more. this time for ps -A
if ((pid = fork()) < 0)
{
perror("Failed to fork child(3)");
return EXIT_FAILURE;
}
if (pid == 0)
{
// ps -A process.
// stdout = fd1(write)
close(fd2[WRITE]);
close(fd2[READ]);
close(fd1[READ]);
dup2(fd1[WRITE], STDOUT_FILENO);
execlp("ps", "ps", "-A", NULL);
}
int stat=0;
wait(&stat);
return EXIT_SUCCESS;
}
在我的系统上,ps -A
报告了 141 行,其中 41 行在某处包含单词 System
,只需运行 ps -A | 即可验证。 grep 系统 | wc -l <
。上面的代码生成完全相同的输出。
关于c++ - 玩具 shell 管道不正确,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19356075/