linux - 将新行更改为所选行的空格

Question

我有一个文件，其输入如下:

Application handle                         = 36768
  ID of agent holding lock                 = 36433
Application handle                         = 36807
  ID of agent holding lock                 = 53074
Application handle                         = 52994
Application handle                         = 36433
Application handle                         = 36581
  ID of agent holding lock                 = 36580
Application handle                         = 36458

但我想要以下格式的输出:

Application handle                         = 36768  ID of agent holding lock                 = 36433
Application handle                         = 36807  ID of agent holding lock                 = 53074
Application handle                         = 52994
Application handle                         = 36433
Application handle                         = 36581  ID of agent holding lock                 = 36580
Application handle                         = 36458

Answer 1

这个 awk 的工作原理:

awk '$1 == "Application"{if (l) print l; l=$0; next}
     {l=l $0; next} END {print l}' file

Application handle                         = 36768  ID of agent holding lock                 = 36433
Application handle                         = 36807  ID of agent holding lock                 = 53074
Application handle                         = 52994
Application handle                         = 36433
Application handle                         = 36581  ID of agent holding lock                 = 36580
Application handle                         = 36458

说明:

这个 awk 首先评估这个条件:

• $1 == "Application" 检查一行是否以 "Application" 开头。 如果条件匹配，那么它首先执行此操作
  • if (l) print l; 打印 l 的值 if l 不为 null
  • 然后设置l=$0，将变量l的值设置为$0(整行)
  • 最后调用 next 使 awk 移动到下一条记录
• 然后，仅当 $1 != "Application"(要连接的行)时才计算第二个 {...}
• 该 block 是{l=l $0; next} 将第二行附加到变量 l 调用 next
• 这个循环一直持续到最后一行，最后
• END {print l} 被调用以打印最后一行。