为什么以下代码无法编译(链接器错误,未解析的外部符号,class std::basic_ostream<char,struct std::char_traits<char> > & __cdecl operator<<(class std::basic_ostream<char,struct std::char_traits<char> > &,class cClass<int> const &)" (??6@YAAEAV?$basic_ostream@DU?$char_traits@D@std@@@std@@AEAV01@AEBV?$cClass@H@@@Z)
)
#include <iostream>
template <class Type> class Class{
public:
friend std::ostream& operator<<(std::ostream& Stream, const Class& Op);
};
template <class Type> std::ostream& operator<<(std::ostream& Stream, const Class<Type>& Op){
return(Stream);
}
int main(){
Class<int> A;
std::cout << A;
return(0);
}
最佳答案
这一行:
friend std::ostream& operator<<(std::ostream& Stream, const Class& Op);
应该是:
template <class T> friend std::ostream& operator<<(std::ostream& Stream, const Class<T>& Op);
关于C++ 模板和 friend ,链接器错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33983366/