javascript - 比较日期，如果早于今天则删除

Question

如果某个日期早于“今天”，我该如何删除它。如何附加所有项目而不仅仅是日期？我希望我至少走在正确的轨道上。

    var future =  [
     {
       "month":"march",
       "day":1,
       "year":2014,
       "movie":"thor"
       },
     {
       "month":"may",
       "day":29,
       "year":2020,
       "movie":"superman"
       },
     {
       "month":"may",
       "day":29,
       "year":2020,
       "movie":"batman"
       }
    ];

   var afterToday = [];

   future.forEach(function(item){
       var today = new Date();
       var zzz =  new Date(item.day + " " + item.month + " " + item.year);
       if(zzz > today)
       {
         afterToday[length] = zzz;
           $('body').append(afterToday);
       }

Answer 1

对于现代浏览器尝试

var future = [{
    "month": "march",
    "day": 1,
    "year": 2014
}, {
    "month": "may",
    "day": 29,
    "year": 2020
}, {
    "month": "may",
    "day": 16,
    "year": 2014
}];

var array = ['jan', 'feb', 'march', 'april', 'may'];
var today = new Date();
today.setHours(0);
today.setMinutes(0);
today.setSeconds(0);
today = today.setMilliseconds(0);
future = future.filter(function (value) {
    return new Date(value.year, array.indexOf(value.month), value.day) >= today;
})

console.log(future)

演示:Fiddle

---

使用 jQuery 跨浏览器

future = $.grep(future, function(value){
    return new Date(value.year, $.inArray(array, value.month), value.day) > today;
})

演示:Fiddle