javascript - 解构对象数组 (es6)

Question

我想知道如何解构对象数组。我正在尝试从 partner 数组中解构 country 。项目要求合作伙伴是对象的数组，即使每个对象只能有一个合作伙伴国家/地区。

arr = [
   { title: "Title A",
     desc: "Desc A",
     role: {role_desc: "Role Desc A", role_name: "Role A"},
     partner: [{country: "Brazil", region: "SA"}]
   },
   { title: "Title B",
     desc: "Desc B",
     role: {role_desc: "Role Desc B", role_name: "Role B"},
     partner: [{country: "US", region: "NA"}]
   }
]

我能够使用除合作伙伴之外的所有字段的数据填充表格。

arr.map(
  ({ title, desc, role: {role_name}, partner: [{country}] }) => 
  ({ title, desc, role: {role_name}, partner: [{country}] })
);

我提到了Destructure object properties inside array for all elements和 Destructuring an array of objects with es6 ，看起来如果不先转换数据就不可能做到这一点。

任何帮助将不胜感激(并对骗子表示歉意)。

Answer 1

当你想处理partner为空数组的情况时，你可以简单地使用默认值，

const arr = [{ title: "Title A",desc: "Desc A",role: {role_desc: "Role Desc A", role_name: "Role A"},partner: [{country: "Brazil", region: "SA"}]},{ title: "Title B",desc: "Desc B",role: {role_desc: "Role Desc B", role_name: "Role B"},partner: [{country: "US", region: "NA"}]},{ title: "Title C",desc: "Desc C",role: {role_desc: "Role Desc C", role_name: "Role C"},partner: []}]

const final = arr.map(
  ({ title, desc, role: {role_name}, partner}) => 
  ({ title, desc, role: {role_name}, partner:[ {country} = {country: undefined } ] })
);

console.log(final)

---

话虽这么说，我们应该尽可能保持代码的可读性，但在这里它变得很难看，而不是试图保存额外的一行，我们应该选择使其更具可读性

const arr = [{ title: "Title A",desc: "Desc A",role: {role_desc: "Role Desc A", role_name: "Role A"},partner: [{country: "Brazil", region: "SA"}]},{ title: "Title B",desc: "Desc B",role: {role_desc: "Role Desc B", role_name: "Role B"},partner: [{country: "US", region: "NA"}]},{ title: "Title C",desc: "Desc C",role: {role_desc: "Role Desc C", role_name: "Role C"},partner: []}]

const final = arr.map(
  ({ title, desc, role: {role_name}, partner}) => {
     let country = partner[0] && partner[0].country || undefined
    return { title, desc, role: {role_name}, partner:[ {country}] }
  }
);

console.log(final)