javascript - 从对象数组中收集键并将其缩减为单个数组并删除重复项

Question

我正在尝试提取数组中每个对象的键，然后我将收集所有键，然后连接小块键数组。然后我使用 set 来消除重复项并获取所有 key 。

我能够得到结果。有没有更好的方法呢

感谢任何帮助

let data = [
  {
    "test1": "123",
    "test2": "12345",
    "test3": "123456"
  },
  {
    "test1": "123",
    "test2": "12345",
    "test3": "123456"
  },
  {
    "test1": "123",
    "test2": "12345",
    "test3": "123456"
  },
  {
    "test1": "123",
    "test2": "12345",
    "test3": "123456"
  },
  {
    "test1": "123",
    "test2": "12345",
    "test3": "123456"
  },
]

let keysCollection = []

data.forEach(d => {
  let keys = Object.keys(d);
  keysCollection.push(keys)
})


let mergingKeysCollection = keysCollection.reduce((a,b) => [...a, ...b], [])

let uniqueKeys = new Set(mergingKeysCollection)

console.log('uniqueKeys', uniqueKeys)

Answer 1

您可以直接获取一个集合，而无需使用另一个键数组。

let data = [{ test1: "123", test2: "12345", test3: "123456" }, { test1: "123", test2: "12345", test3: "123456" }, { test1: "123", test2: "12345", test3: "123456" }, { test1: "123", test2: "12345", test3: "123456" }, { test1: "123", test2: "12345", test3: "123456" }],
    uniqueKeys = Array.from(
        data.reduce((r, o) => Object.keys(o).reduce((s, k) => s.add(k), r), new Set)
    );

console.log(uniqueKeys)